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python - 给定未排序的其他约束,标准化数据框中的值

转载 作者:行者123 更新时间:2023-12-01 03:17:24 25 4
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我有一个如下所示的数据框:

            counter leg_rate pose_rate component    approach      rmse
0 proc/stat-stime d d test Baseline 1.583097
1 proc/stat-stime d r test AEW - MTEN 0.516108
2 proc/stat-stime d d test ASDF 0.705861
3 proc/stat-stime r r test ASDF 0.345816
4 proc/stat-utime d r test Baseline 1.128632
5 proc/stat-stime d r test Baseline 1.579803
6 proc/stat-stime r r test Baseline 1.345895
7 proc/stat-utime r r test AEW - MTEN 0.187236
8 proc/stat-utime d d test Baseline 1.193776
9 proc/stat-stime r d test ASDF 0.014975
10 proc/stat-utime r r test ASDF 0.985493
11 proc/stat-utime r d test AEW - MTEN 0.897336
12 proc/stat-stime r d test Baseline 1.415103
13 proc/stat-utime r d test Baseline 1.724266
14 proc/stat-utime r r test Baseline 1.294654
15 proc/stat-utime d d test AEW - MTEN 0.263845
16 proc/stat-utime r d test ASDF 0.497368
17 proc/stat-stime d d test AEW - MTEN 0.143402
18 proc/stat-utime d r test AEW - MTEN 0.233437
19 proc/stat-stime r d test AEW - MTEN 0.431739
20 proc/stat-utime d r test ASDF 0.002475
21 proc/stat-stime d r test ASDF 0.331700
22 proc/stat-stime r r test AEW - MTEN 0.985123
23 proc/stat-utime d d test ASDF 0.464989

我想通过将 rmse 除以名为 Baseline方法中的值来标准化它。最后应该有一个新列 rmse-norm ,其中包含相应的标准化值。所有其他列基本上都提供了划分 rmse 时需要匹配的上下文。这意味着该行

1   proc/stat-stime        d         r      test  AEW - MTEN  0.516108

需要除以与其他列匹配的行

5   proc/stat-stime        d         r      test    Baseline  1.579803

Baseline 方法中总会有一个匹配的行。

我已经尝试使用 groupby 并使用其他列的索引进行各种操作,但由于列的顺序未知,我无法想出一些简洁的方法来为正确的值分配正确的值订购。

最佳答案

我认为你可以使用:

#filter all rows with Baseline to `MultiIndex` `Series`
cols = ['counter','leg_rate','pose_rate','component']
s = df[df.approach == 'Baseline'].set_index(cols)['rmse']
print (s)
counter leg_rate pose_rate component
proc/stat-stime d d test 1.583097
proc/stat-utime d r test 1.128632
proc/stat-stime d r test 1.579803
r r test 1.345895
proc/stat-utime d d test 1.193776
proc/stat-stime r d test 1.415103
proc/stat-utime r d test 1.724266
r test 1.294654
Name: rmse, dtype: float64
#sorting for matching, because set_index sort index
df = df.sort_values(cols)
#divide by s, output to numpy array for assign to rmse column
df['rmse'] = df.set_index(cols)['rmse'].div(s).values
#sort index to original unsorted df
print (df.sort_index())
counter leg_rate pose_rate component approach rmse
0 proc/stat-stime d d test Baseline 1.000000
1 proc/stat-stime d r test AEW - MTEN 0.326691
2 proc/stat-stime d d test ASDF 0.445873
3 proc/stat-stime r r test ASDF 0.256941
4 proc/stat-utime d r test Baseline 1.000000
5 proc/stat-stime d r test Baseline 1.000000
6 proc/stat-stime r r test Baseline 1.000000
7 proc/stat-utime r r test AEW - MTEN 0.144622
8 proc/stat-utime d d test Baseline 1.000000
9 proc/stat-stime r d test ASDF 0.010582
10 proc/stat-utime r r test ASDF 0.761202
11 proc/stat-utime r d test AEW - MTEN 0.520416
12 proc/stat-stime r d test Baseline 1.000000
13 proc/stat-utime r d test Baseline 1.000000
14 proc/stat-utime r r test Baseline 1.000000
15 proc/stat-utime d d test AEW - MTEN 0.221017
16 proc/stat-utime r d test ASDF 0.288452
17 proc/stat-stime d d test AEW - MTEN 0.090583
18 proc/stat-utime d r test AEW - MTEN 0.206832
19 proc/stat-stime r d test AEW - MTEN 0.305094
20 proc/stat-utime d r test ASDF 0.002193
21 proc/stat-stime d r test ASDF 0.209963
22 proc/stat-stime r r test AEW - MTEN 0.731946
23 proc/stat-utime d d test ASDF 0.389511

使用groupby和自定义函数f的另一个解决方案:

def f(x):
x.rmse = x['rmse'] / x.loc[x['approach'] == 'Baseline', 'rmse'].item()
return x

df = df.groupby(['counter','leg_rate','pose_rate','component']).apply(f)
print (df)
counter leg_rate pose_rate component approach rmse
0 proc/stat-stime d d test Baseline 1.000000
1 proc/stat-stime d r test AEW - MTEN 0.326691
2 proc/stat-stime d d test ASDF 0.445873
3 proc/stat-stime r r test ASDF 0.256941
4 proc/stat-utime d r test Baseline 1.000000
5 proc/stat-stime d r test Baseline 1.000000
6 proc/stat-stime r r test Baseline 1.000000
7 proc/stat-utime r r test AEW - MTEN 0.144622
8 proc/stat-utime d d test Baseline 1.000000
9 proc/stat-stime r d test ASDF 0.010582
10 proc/stat-utime r r test ASDF 0.761202
11 proc/stat-utime r d test AEW - MTEN 0.520416
12 proc/stat-stime r d test Baseline 1.000000
13 proc/stat-utime r d test Baseline 1.000000
14 proc/stat-utime r r test Baseline 1.000000
15 proc/stat-utime d d test AEW - MTEN 0.221017
16 proc/stat-utime r d test ASDF 0.288452
17 proc/stat-stime d d test AEW - MTEN 0.090583
18 proc/stat-utime d r test AEW - MTEN 0.206832
19 proc/stat-stime r d test AEW - MTEN 0.305094
20 proc/stat-utime d r test ASDF 0.002193
21 proc/stat-stime d r test ASDF 0.209963
22 proc/stat-stime r r test AEW - MTEN 0.731946
23 proc/stat-utime d d test ASDF 0.389511

关于python - 给定未排序的其他约束,标准化数据框中的值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42341278/

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