javascript - 如何使用函数式编程过滤多个路径

Question

我有以下伪代码:

let array = getData();
array.filter(x => condition1(x)).doSomething1...
array.filter(x => condition2(x)).doSomething2...
array.filter(x => condition3(x)).doSomething3...

显然这效率不高，因为它迭代了数组 3 次。

我想知道是否有办法做这样的事情:

array.filterMany([
    x => condition1(x).doSomething1...,
    x => condition2(x).doSomething2...,
    x => condition3(x).doSomething3...
])

这样数组就只迭代一次？

Answer 1

像这样怎么样？

const condition1 = x => x === 1;
const condition2 = x => x === 2;
const condition3 = x => x === 3;

[1, 2, 3].map(n => {
  condition1(n) && console.log('foo');
  condition2(n) && console.log('bar');
  condition3(n) && console.log('baz');
})