Python Int 对象不可调用

Question

请帮忙!我不明白这里的错误。当我输入 0、1 或 2 以外的数字时，为什么会收到错误消息:“‘int’对象不可调用”？相反，它应该打印“您输入了错误的数字，请重试”并返回询问问题。

第二个问题:另外，如何更改代码，即使我输入字母字符，也不会给出值错误并继续重新提出问题？谢谢!

def player_action():        
    player_action = int(input("Enter 0 to stay, 1 to go Up, or 2 to go Down: "))

    if player_action == 0:
        print ("Thank You, you chose to stay")


    if player_action == 1:
        print ("Thank You, you chose to go up")

    if player_action == 2:
        print ("Thank You, you chose to go down")

    else:
        print ("You have entered an incorrect number, please try again")
        player_action()

player_action()

Answer 1

您应该按照@Pedro Lobito的建议更改变量名称，按照@Craig的建议使用while循环，并且还可以包含try... except语句，但不是 @polarisfox64 的做法，因为他把它放在了错误的位置。

以下是完整版本供您引用:

def player_action():    
    while True:   
        try:
            user_input = int(input("Enter 0 to stay, 1 to go Up, or 2 to go Down: "))
        except ValueError:
            print('not a number')
            continue

        if user_input == 0:
            print ("Thank You, you chose to stay")          

        if user_input == 1:
            print ("Thank You, you chose to go up")

        if user_input == 2:
            print ("Thank You, you chose to go down")

        else:
            print ("You have entered an incorrect number, please try again")
            continue
        break

player_action()