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javascript - Angular 2 : Convert a complex JSON Object to a Simple one

转载 作者:行者123 更新时间:2023-12-01 03:04:08 25 4
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我对 Angular 2 很陌生,我遇到了一个问题,我必须从 REST API 获取的 JSON 对象中过滤掉所有不必要的内容。以下是我收到的 JSON 示例。

{  
"refDataId":{
"rdk":1,
"refDataTypeCD":"CNTRY",
"refDataStatusCD":"C",
"effStartDT":"2017-09-01",
"effEndDT":null,
"updtUserID":"EDMO",
"updtTS":"2017-09-05"
},
"refDataDescs":[
{
"rdk":1,
"langCD":"EN_CA",
"refDataNM":"Not Applicable",
"refDataShortNM":null,
"refDataDesc":"Not issued by ISO. Dummy country code for internal reference use only.",
"updtUserID":"EDMO",
"updtTS":"2017-09-05"
}
],
"refCntry":{
"cntryRdk":1,
"cntryIso2DigitCD":"0",
"cntryIso3DigitCD":null,
"cntryIsoNumericCD":0,
"riskTypeRdk":0
}

}

{  
"refDataId":{
"rdk":2,
"refDataTypeCD":"CNTRY",
"refDataStatusCD":"C",
"effStartDT":"2017-09-01",
"effEndDT":null,
"updtUserID":"EDMO",
"updtTS":"2017-09-05"
},
"refDataDescs":[
{
"rdk":2,
"langCD":"EN_CA",
"refDataNM":"Afghanistan",
"refDataShortNM":null,
"refDataDesc":null,
"updtUserID":"EDMO",
"updtTS":"2017-09-05"
}

我从这些数据中需要的只是这两个字段: “rdk”:2, "refDataNM":"阿富汗"

我需要过滤掉这些数据,然后仅用这些数据形成一个新的 JSON 数组。像这样的事情:

{"id":2,"itemName":"Afghanistan"},
{"id":3,"itemName":"Albania"}

最佳答案

你可以尝试这样的事情:

filterDate(input:any[]) {
const output=[];
input.foreach( item => output.push({"id": item.refDataId.id, "itemName": item.refDataDescs.refDataNM}));
return output;
}

关于javascript - Angular 2 : Convert a complex JSON Object to a Simple one,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46310298/

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