python - 在文本文件中打印字符百分比

Question

我刚刚编写了一个在文本文件中打印字符百分比的函数。但是，我遇到了一个问题。我的程序将大写字符计算为不同的字符，并计算空格。这就是为什么结果是错误的。我该如何解决这个问题？

def count_char(text, char):
    count = 0
    for character in text:
        if character == char:
            count += 1
    return count

filename = input("Enter the file name: ")
with open(filename) as file:
    text = file.read()

for char in "abcdefghijklmnopqrstuvwxyz":
    perc = 100 * count_char(text, char) / len(text)
    print("{0} - {1}%".format(char, round(perc, 2)))

Answer 1

您应该尝试使用 text.lower() 将文本设为小写。然后为了避免计算空格，您应该使用以下命令将字符串拆分为列表: text.lower().split() 。这应该做:

def count_char(text, char):
    count = 0
    for word in text.lower().split():  # this iterates returning every word in the text
        for character in word:   # this iterates returning every character in each word
            if character == char:
                count += 1
    return count

filename = input("Enter the file name: ")
with open(filename) as file:
    text = file.read()

totalChars = sum([len(i) for i in text.lower().split()]

for char in "abcdefghijklmnopqrstuvwxyz":
    perc = 100 * count_char(text, char) / totalChars
    print("{0} - {1}%".format(char, round(perc, 2)))

注意perc中的变化定义，sum([len(i) for i in text.lower().split()]返回单词列表中的字符数 len(text)还计算空格。