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python - 如何与无限循环同时运行 Bottle?

转载 作者:行者123 更新时间:2023-12-01 02:53:45 26 4
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我正在尝试将 Bottle.py 作为脚本内的进程运行,但我很沮丧,因为它没有按我的预期工作。这是我的脚本的假设/简化表示。我尝试添加尽可能多的评论。

magball.py

import serial
from bottle import route, run, template, request
import multiprocessing
import logging
import datetime


#Here are the most important variables which will be used in the entire script
global lastcommand #The last command received from bottle web interface
global status #What is the current status

lastcommand = 'Go Home' #Options: Start Drawing, Go Home, Next Drawing
status = 'home' #Options: home, homing (means going home), drawing

def log_this(level, msg)
#a special log function based on logging library for debugging
pass # <- details are not important, it is working fine

now = datetime.datetime.now()
timeString = now.strftime("%Y-%m-%d %H:%M")
info = {'title' : 'MAGBALL', 'time': timeString, 'lastcommand': lastcommand, 'status': status} #These are passed to main.tpl
@route('/', method='GET')
@route('/', method='POST')
def index(): #<- This works fine, passing the info to the template file (main.tpl) in views directory
global lastcommand #<- Isn't this referring to the global lastcommand declared at the beginning?
if request.method == 'POST':
lastcommand = request.forms.get("submit") #<- This works fine and lastcommand changes when the button on the web page is clicked
log_this('info', (lastcommand + ' clicked on web interface')) #<- I can see in the logs which button is clicked, so, this should mean
#that lastcommand (supposedly the global one) was changed successfully

return template('main.tpl', info)

p_bottle = multiprocessing.Process(target=run, kwargs=dict(host='0.0.0.0', port=80, debug='True')) #<- I start bottle as a process because I think I have to
p_bottle.daemon = True

def draw_pattern() #<- This function can easily run for hours which is fine/normal for the purpose
#Unless lastcommand is not equal to 'Start Drawing' this should run forever
global status
global lastcommand
status = 'drawing' #<- I think this should also refer to the global lastcommand declared at the beginning
#Opens a random file from a specific directory,
for filename in shuffled_directory:
#reads the file line by line and feeds it to the serial port
.
.
if lastcommand != 'Start Drawing': #<- This never works! Although I see in the logs that lastcommand was changed by index() function
log_this('warning', 'Last command changed during line feeding.')
break

def go_home()
global status
status = 'homing' #<- I think this should also refer to the global lastcommand declared at the beginning
#Send some commands to serial port and after that change the value of status
.
.
status = 'home'

while true: #This is the infinite loop that needs to run forever
global status #Don't these variables also refer to the global variables declared at the beginning?
global lastcommand
p_bottle.start() #The bottle.py web interface runs successfully
#The following while, if etc never runs. I think this "while true:" statement never gets notified
#that the values of lastcommand and/or status has changed
while lastcommand == 'Start Drawing':
if status == 'home':
draw_pattern()
if status == 'homing':
time.sleep(5)
if status == 'drawing':
pass
while lastcommand == 'Next Drawing':
if status == 'home':
draw_pattern()
if status == 'homing':
time.sleep(5)
if status == 'drawing':
go_home()
draw_pattern()
while lastcommand == 'Go Home':
if status == 'home':
pass
if status == 'homing':
pass
if status == 'drawing':
go_home()

main.tpl

<!DOCTYPE html>
<head>
<title>{{ title }}</title>
</head>
<body>
<h1>Magball Web Interface</h1>
<h2>The date and time on the server is: {{ time }}</h2>
<h2>The last command is: {{ lastcommand }}</h2>
<h2>Status: {{ status }}</h2>
<form name='magballaction' method='POST'>
<input type="submit" name="submit" value="Start Drawing">
<input type="submit" name="submit" value="Go Home">
<input type="submit" name="submit" value="Next Drawing">
</form>
</body>
</html>

发生的事情是这样的:
Bottle 进程运行良好(网页可访问),当我单击网页上的按钮时,我在日志中看到 Lastcommand 的值已被 Web 界面更改。

然而,最后的无限循环 (while true:) 永远不会收到有关 lastcommand 的值已更改的通知。例如,如果 status = home 且 lastcommand 从 Web 界面更改为“Start Drawing”,则它不会执行 draw_pattern()。它什么也不做。

我尝试将所有内容放入 def index() 函数中 return template('main.tpl', info) 行之前,但随后代码运行,但是Web 界面等待代码完成才能启动。由于 draw_pattern() 持续数小时,return template('main.tpl', info) 行实际上不会运行,并且网页无法访问。

我还尝试将 def index() 作为普通函数运行,但是当我这样做时,唯一运行的是 Web 界面 (def index()) >).

那么,我该怎么做才能通知 while 循环 Lastcommand 和/或状态的值已更改?

最佳答案

对于任何感兴趣的人,我已经使用线程而不是多处理解决了这个问题。因此,不要使用这个:

p_bottle = multiprocessing.Process(target=run, kwargs=dict(host='0.0.0.0', port=80, debug='True')) 
p_bottle.daemon = True

我用过:

p_bottle = threading.Thread(target=run, kwargs=dict(host='0.0.0.0', port=80, debug='True'))
p_bottle.daemon = True

现在线程中的函数可以成功更改全局变量,该全局变量会立即被无限 while true 循环获取。谢谢大家的建议。

关于python - 如何与无限循环同时运行 Bottle?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44451364/

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