javascript - 让 var 根据 if 语句返回特定值

Question

我写了一个 for 循环来唱《墙上的 99 瓶啤酒》。我正在使用 if 语句将特定值返回到 var word。当瓶子数量为 99 比 2 时，则 var word="bottles"；当瓶子数量为 1 时，则 var word = "bottle"。这工作正常，但在最终迭代的最后一行，当瓶子数量为 0 并且我希望 var word 等于“bottles”时，它仍然显示为“bottle”。

var word="bottles";
for (var count = 99; count > 0; count-- ) { 
   document.write(count + " " + word + " of beer on the wall, <br>");
    document.write(count + " " + word + " of beer.<br>" );
    document.write("Take one down, pass it around,<br>");
    var count2 = count - 1;
        if (count2 === 1) {
        word = "bottle";
        }
    document.write(count2 + " " + word + " of beer on the wall.<br><br>");
    }   

我的if语句的条件不正确吗？这就是最后三个迭代在浏览器中的样子:

墙上挂着3瓶啤酒，3瓶啤酒。拿下来一张传给大家墙上挂着两瓶啤酒。

墙上挂着两瓶啤酒，2瓶啤酒。拿下来一张传给大家墙上挂着一瓶啤酒。

墙上挂着一瓶啤酒，1瓶啤酒。拿下来一张传给大家墙上有 0 瓶啤酒。

Answer 1

您错过了重置为瓶子的else部分，请尝试使用此脚本

var word="bottles";
for (var count = 99; count > 0; count-- ) { 
   document.write(count + " " + word + " of beer on the wall, <br>");
    document.write(count + " " + word + " of beer.<br>" );
    document.write("Take one down, pass it around,<br>");
    var count2 = count - 1;
        if (count2 === 1) {
        word = "bottle";
        } else
	{ word = "bottles";
	}
    document.write(count2 + " " + word + " of beer on the wall.<br><br>");
    }