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javascript - 锁定/防止关闭菜单reactjs

转载 作者:行者123 更新时间:2023-12-01 02:47:01 29 4
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我有一个侧面菜单,单击图标时打开,单击页面或单击菜单上的项目时关闭。我正在尝试实现锁定,因此当单击锁定图标时,即使您单击菜单项或页面,菜单也不会关闭。

我能够将图标从锁定图标更改为解锁图标,但我在停止关闭功能方面遇到问题。任何帮助/建议都会很棒。下面是 2 个组件(父组件和带有锁定按钮的菜单),这是完整外观的代码沙箱:https://codesandbox.io/s/pw6q46jp20

class SideBar extends Component {
constructor(props) {
super(props);
this.state = {
category: props.category,
currentPage: {
backgroundColor: '#383838',
color: '#A9A9A9',
},
menuLocked: false,
menuOpen: false,
selectedIcon: null,
};
}
handleIconClick = (category) => {
this.setState({
category,
menuOpen: true,
selectedIcon: category,
});
};
handleMenuItemClick = (category) => {
this.setState({
menuOpen: false,
selectedIcon: '',
currentPage: category,
});
}
handlePageClick = () => {
this.setState({
menuOpen: false,
});
}
handleMenuLock = () => {
this.setState({ menuLocked: !this.state.menuLocked });
}
render() {
return (
<div>
<TopBar {...this.props} />
<Container>
<SideNav>
<ListWrapper>
<IconList
currentPage={this.state.currentPage}
openMenu={this.handleIconClick}
selectedIcon={this.state.selectedIcon}
visible={this.state.menuOpen}
/>
</ListWrapper>
</SideNav>
<PageContentWrapper>
<Sidebar.Pushable>
<PushMenu
category={this.state.category}
closeOnItemClick={this.handleMenuItemClick}
handleMenuLock={this.handleMenuLock}
menuLocked={this.state.menuLocked}
params={this.props.params}
visible={this.state.menuOpen}
/>
<Sidebar.Pusher
onClick={this.handlePageClick}>
<Segment basic>
{this.props.children || <Home />}
</Segment>
</Sidebar.Pusher>
</Sidebar.Pushable>
</PageContentWrapper>
</Container>
</div>
);
}
}

SideBar.propTypes = {
children: PropTypes.any,
params: PropTypes.any,
category: PropTypes.any,
};

export default SideBar;

class PushMenu extends React.Component {
render() {
const category = sideNavData.lookupCategory(this.props.category);
const menuLockButton = !this.props.menuLocked
? <Icon
link={true}
name='unlock'
size='big'
/>
: <Icon
link={true}
name='lock'
size='big'
/>;
return (
<Sidebar
className='Push-menu'
animation='push'
width='thin'
visible={this.props.visible}
>
<Header>{this.props.category}</Header>
<Linebreak />
{
Object.keys(category).map((subCategory, index) => {
return (
<div key={index}>
<SubcategoryHeader>{subCategory}</SubcategoryHeader>
<List>
{
Object.keys(category[subCategory]).map((item, index) => (
<li key={index}>
<ListLink>
<Link
to={`/${this.props.category}/${subCategory}/${category[subCategory][item].name}`}
activeStyle={{ color: '#FFFFFF' }}
onClick={() => {
this.props.closeOnItemClick(this.props.category);
}}
>
{category[subCategory][item].name}
</Link>
</ListLink>
</li>
))
}
</List>
<LockButtonWrapper onClick={this.props.handleMenuLock}>
{menuLockButton}
</LockButtonWrapper>
</div>
);
})
}
</Sidebar>
);
}
}

PushMenu.propTypes = {
category: PropTypes.any,
closeOnItemClick: PropTypes.func,
currentPage: PropTypes.func,
handleMenuLock: PropTypes.func,
menuLocked: PropTypes.bool,
visible: PropTypes.bool,
};

export default PushMenu;

最佳答案

handlePageClick()内部,您应该检查this.state.menuLocked是否为true。如果是这样,请不要更改 state 中 menuOpen 的值。

handlePageClick = () => {
if (!this.state.menuLocked) {
this.setState({
menuOpen: false,
});
}
}

顺便说一句,在 handleMenuLock() 中,您使用 menuLocked 的先前值来设置新值。由于 setState 是异步的,因此 menuLocked 的值在实际保存时完全有可能发生变化,因此您可能无法获得所需的结果。因此,您应该向它传递一个像这样的函数:

handleMenuLock = () => {
this.setState((prevState) => ({ menuLocked: !prevState.menuLocked }))
}

这确保了该值确实被切换。有关以这种方式使用 setState 的文档可以在 here 找到。 .

关于javascript - 锁定/防止关闭菜单reactjs,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47190934/

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