php - undefined variable $_POST ['data' ] PHP/Ajax jquery

Question

大家好，这不正常:) !!

foo.php

     <?php 
         if (isset($_POST['data']))
         $stringData = $_POST['data'];
         $file = "ciao.txt"; 
         $fh = fopen($file, 'w') or die("can't open file");
         fwrite($fh, $stringData);
         fclose($fh); 

         ?>

file.js

    function WriteToFile() {
        var dataa = "foo bar";
     $.post("foo.php", {data: dataa}, function(result){ alert("ciaoooo!!");}            
           , "json");
    }

这是错误，我无法在我的 file.txt 上写入

注意: undefined variable :stringData

我也尝试过这种功能

function WriteToFile() {
    var data = "foo bar";
$.ajax({
    url: 'foo.php',
    type: 'POST',
    data: { 'data' : 'data'},
    success: function() {
        alert('the data was successfully sent to the server');
    }
});

but the result is the same!! Anyone have some idea???

Answer 1

您缺少大括号:

if (isset($_POST['data'])) {
         $stringData = $_POST['data'];
         $file = "ciao.txt"; 
         $fh = fopen($file, 'w') or die("can't open file");
         fwrite($fh, $stringData);
         fclose($fh); 
 }

没有它们，你基本上就会得到这个:

 if (isset($_POST['data'])) {
         $stringData = $_POST['data'];
 }
 $file = "ciao.txt"; 
 $fh = fopen($file, 'w') or die("can't open file");
 fwrite($fh, $stringData);
 fclose($fh); 

这解释了为什么您会得到未定义的 $stringData，因为 POST 未正确执行。

请注意，这并不能解决您的 JS/jQuery 问题。为此，请参阅其他答案。