javascript - 如何返回与key匹配的json键？

Question

我正在尝试返回一些键并将其与特定值进行匹配。

如果错误键包含“密码”，那么我只想返回带有密码的错误键，在本例中删除带有firstname_empty的错误键。

我想出了这个，但即使在改变了一些逻辑之后，我最终还是因为某种原因返回了所有 3 个。

var key = "password";

var errors = [{
  "password_empty": "Password is empty",
  "firstname_empty": "First name is required",
  "password_min": "Password needs a min of 6 chars"
}];

for(var i in errors){
    if(errors.match(key)){
        console.log(errors[i]);
    }
}

Answer 1

获得所需结果的方法有多种，具体取决于您是要保留原始数据结构并返回新数据结构，还是要改变原始数据。

1)改变原始数据结构 - 从对象中删除属性。

var errors = [{
  "password_empty": "Password is empty",
  "firstname_empty": "First name is required",
  "password_min": "Password needs a min of 6 chars"
}];

function byKeyword(obj, keyword) {
  for (let key in obj) {
    if (!key.includes(keyword)) delete obj[key];
  }
  return [obj];
}

let result = byKeyword(errors[0], 'password');
console.log(result);

2) 对对象进行简单循环，将匹配的属性添加到临时对象。

var errors = [{
  "password_empty": "Password is empty",
  "firstname_empty": "First name is required",
  "password_min": "Password needs a min of 6 chars"
}];

function byKeyword(obj, keyword) {
  const temp = {};
  for (let key in obj) {
    if (key.includes(keyword)) temp[key] = obj[key];
  }
  return [temp];
}

let result = byKeyword(errors[0], 'password');
console.log(result);

3) 与 2 类似，但使用 reduce .

var errors = [{
  "password_empty": "Password is empty",
  "firstname_empty": "First name is required",
  "password_min": "Password needs a min of 6 chars"
}];

function byKeyword(obj, keyword) {
  return Object.keys(obj).reduce((acc, key) => {
    if (key.includes(keyword)) acc[0][key] = obj[key];
    return acc;
  }, [{}]);
}

let result = byKeyword(errors[0], 'password');
console.log(result);

编辑:要获取属性值，您只能再次使用循环...

function byKeyword(obj, keyword) {
  const temp = [];
  for (let key in obj) {
    if (key.includes(keyword)) temp.push(obj[key]);
  }
  return temp;
}

...或减少。

function byKeyword(obj, keyword) {
  return Object.keys(obj).reduce((acc, key) => {
    if (key.includes(keyword)) acc.push(obj[key]);
    return acc;
  }, []);
}

希望这有用。