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python - pygame/python 不会检测 Sprite 之间的碰撞

转载 作者:行者123 更新时间:2023-12-01 02:40:24 24 4
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我试图检测 pacman 和盒子之间的碰撞,但它没有检测到任何碰撞,有什么帮助或建议吗?目前我尝试创建一个实例列表,但没有成功,我不知道还能做什么。它还告诉我添加更多细节,但说实话,我真的不知道可以添加什么,抱歉

import pygame
import os
import sys

#intialise the game
pygame.init()
screen = pygame.display.set_mode((448, 576))
done = False

y = 320
x = 216

#sets up clock and loads pacman image
clock = pygame.time.Clock()
PACMANSPRITE = pygame.image.load("pacman.png").convert_alpha()

#gets pacman intro music, sets music to lower volume then plays it
pygame.mixer.music.load('pacman_beginning.WAV')
pygame.mixer.music.set_volume(0.01)
pygame.mixer.music.play(0)


#box class, used for boxes to border pacmans map
class boxcollisions(pygame.sprite.Sprite):
def __init__(self, x, y):
self.y = y
self.x = x
self.rect = pygame.Rect(self.x, self.y, 15, 15)
self.color = (0, 128, 255)

def draw(self, screen):
pygame.draw.rect(screen, self.color, self.rect)



#pacmans class
class pacman(pygame.sprite.Sprite):
def __init__(self, image, x, y):
self.image = image
self.y=y
self.x=x
self.rect = self.image.get_rect()
self.rect.left = self.x
self.rect.top = self.y
self.rect.width=16
self.rect.height=16


# move pacman
def movement(self):
pressed= pygame.key.get_pressed()
if pressed[pygame.K_UP]:
self.y -= 2
if pressed[pygame.K_DOWN]:
self.y += 2
if pressed[pygame.K_LEFT]:
self.x -= 2
if pressed[pygame.K_RIGHT]:
self.x += 2


def draw(self, surface):
""" Draw on surface """
# blit yourself at your current position
surface.blit(self.image, (self.x, self.y))

#instances the pacman class
sprite = pacman(PACMANSPRITE, x ,y)


#main game loop
while not done:
for event in pygame.event.get():
if event.type == pygame.QUIT:
done = True
pygame.quit()
sys.exit()


screen.fill((100,0,0))

#co-ordinates for boxes to set up map boundaries
boundaries=[

[],
[],
[],
[1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28],
[1,14,15,28], #5
[1,3,4,5,6,8,9,10,11,12,14,15,17,18,19,20,21,23,24,25,26,28],
[1,3,4,5,6,8,9,10,11,12,14,15,17,18,19,20,21,23,24,25,26,28],
[1,3,4,5,6,8,9,10,11,12,14,15,17,18,19,20,21,23,24,25,26,28],
[1,28],
[1,3,4,5,6,8,9,11,12,13,14,15,16,17,18,20,21,23,24,25,26,28], #10
[1,3,4,5,6,8,9,11,12,13,14,15,16,17,18,20,21,23,24,25,26,28],
[1,8,9,14,15,20,21,28],
[1,2,3,4,5,6,8,9,10,11,12,14,15,17,18,19,20,21,23,24,25,26,27,28],
[1,2,3,4,5,6,8,9,10,11,12,14,15,17,18,19,20,21,23,24,25,26,27,28],
[6,8,9,20,21,23], #15
[6,8,9,11,12,13,14,15,16,17,18,20,21,23],
[1,2,3,4,5,6,8,9,11,12,13,14,15,16,17,18,20,21,23,24,25,26,27,28],
[1,11,12,13,14,15,16,17,18,28],
[1,2,3,4,5,6,8,9,11,12,13,14,15,16,17,18,20,21,23,24,25,26,27,28],
[6,8,9,11,12,13,14,15,16,17,18,20,21,23,24,25,26,27,28], #20
[6,8,9,20,21,23],
[6,8,9,11,12,13,14,15,16,17,18,20,21,23],
[1,2,3,4,5,6,8,9,11,12,13,14,15,16,17,18,20,21,23,24,25,26,27,28],
[1,14,15,28],
[1,3,4,5,6,8,9,10,11,12,14,15,17,18,19,20,21,23,24,25,26,28], #25
[1,3,4,5,6,8,9,10,11,12,14,15,17,18,19,20,21,23,24,25,26,28],
[1,5,6,23,24,28],
[1,2,3,5,6,8,9,11,12,13,14,15,16,17,18,20,21,23,24,26,27,28],
[1,2,3,5,6,8,9,11,12,13,14,15,16,17,18,20,21,23,24,26,27,28],
[1,8,9,14,15,20,21,28], # 30
[1,3,4,5,6,7,8,9,10,11,12,14,15,17,18,19,20,21,22,23,24,25,26,28],
[1,3,4,5,6,7,8,9,10,11,12,14,15,17,18,19,20,21,22,23,24,25,26,28],
[1,28],
[1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28],

]

#builds the boxes
bx=0
by=-16
for row in boundaries:
#y co ordinate
by=by+16
for n in row:
#x co ordinate
n=n-1
bx=n*16
box = boxcollisions(bx, by)
box.draw(screen)


#moves pacman
sprite.movement()
sprite.draw(screen)

#tests for collision
print(pygame.sprite.collide_rect(sprite, box))



pygame.display.flip()
clock.tick(60)

最佳答案

1 - 您需要更新运动方法的顶部和左侧位置。看:

# move pacman 
def movement(self):
pressed= pygame.key.get_pressed()
if pressed[pygame.K_UP]:
self.y -= 2
if pressed[pygame.K_DOWN]:
self.y += 2
if pressed[pygame.K_LEFT]:
self.x -= 2
if pressed[pygame.K_RIGHT]:
self.x += 2
self.rect.left = self.x
self.rect.top = self.y

2 - 您必须在循环中验证碰撞,以验证所有框

for row in boundaries:
#y co ordinate
by=by+16
for n in row:
#x co ordinate
n=n-1
bx=n*16
box = boxcollisions(bx, by)
box_list.append(box)
box.draw(screen)
if pygame.sprite.collide_rect(sprite, box):
print("collided")

关于python - pygame/python 不会检测 Sprite 之间的碰撞,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45772836/

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