python-3.x - Popen 的上下文管理器

Question

我对 Python 非常陌生。我在 Context Manager 上尝试了一个解决方案，如下所示:
问题陈述:
定义一个函数 run_process ，它接受系统命令，在后台运行命令并返回结果

我试过的解决方案:

def run_process:
    with subprocess.Popen(cmd_args) as proc:
        proc.communicate()

if __name__ == "__main__":
    f = open(os.environ['OUTPUT_PATH'], 'w')

    cmd_args_cnt = 0
    cmd_args_cnt = int(input())
    cmd_args_i = 0
    cmd_args = []
    while cmd_args_i < cmd_args_cnt:
        try:
            cmd_args_item = str(input())
        except:
            cmd_args_item = None
        cmd_args.append(cmd_args_item)
        cmd_args_i += 1

    res = run_process(cmd_args);

    if 'with' in inspect.getsource(run_process):
        f.write("'with' used in 'run_process' function definition.\n")

    if 'Popen' in inspect.getsource(run_process):
        f.write("'Popen' used in 'run_process' function definition.\n")
        f.write('Process Output : %s\n' % (res.decode("utf-8")))

    f.close()

预期输入:
3
Python
-C
打印(“你好”)

预期输出:
'run_process' 函数定义中使用的 'with'。
'run_process' 函数定义中使用的 'Popen'。
过程输出:你好

Answer 1

def run_process(cmd_args):
    with subprocess.Popen(cmd_args, stdout=subprocess.PIPE, stderr=subprocess.PIPE) as p:
        out, err = p.communicate()
    return out