python - 如何解决生成饼图时出现Python错误: ValueError: 'explode' must be of length 'x'

Question

任何人都可以帮助我解决使用爆炸选项生成饼图时出现的以下错误。ValueError:“爆炸”的长度必须为“x”

import pandas as pd
import numpy as np
import matplotlib.pyplot as plt
import datetime as dt

figureObject, axesObject = plt.subplots()
labels = "ABC", "XYZ"
delay = [delay1, delay2]
colors  = ("red", "green", "orange", "cyan", "brown", 
"grey","blue","indigo", "beige", "yellow")
explode = (0, 0.1, 0, 0)

# Draw the pie chart
axesObject.pie(delay,
    explode=explode,
    labels=labels,
    colors=colors,
    shadow=True,
    autopct='%1.2f',
    startangle=90,
    wedgeprops = { 'linewidth' : 2, 'edgecolor' : "cyan" })

  plt.legend(patches, labels, loc="best") 

 # Aspect ratio - equal means pie is a circle
  axesObject.axis('equal')
  plt.show()

附加信息:我使用的是 anaconda 3.6 版本。我能够在不爆炸的情况下生成饼图，但是当我使用爆炸时，我收到错误 - ValueError: 'explode' must be of length 'x'.

请帮助我，如何解决这个问题。

Answer 1

主要是阅读 the documentation 有帮助，其中表示

matplotlib.pyplot.pie(x, explode=None ,...)

x : array-like
The input array used to make the pie chart.

explode: array-like, optional, default: None
If not None, is a len(x) array which specifies the fraction of the radius with which to offset each wedge.

因此，如果输入 x 有两个元素，explode 也必须有两个元素，...而不是问题代码中的 4。