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javascript - Jquery 隐藏前 12 个元素,显示后 12 个元素

转载 作者:行者123 更新时间:2023-12-01 02:27:57 26 4
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我想做的是隐藏前 12 个元素并显示接下来的 12 个元素。

//this is dynamic loaded content
<div class="inner-content">
<div class="front-pro">1</div>
<div class="front-pro">2</div>
<div class="front-pro">3</div>
<div class="front-pro">4</div>
<div class="front-pro">5</div>
<div class="front-pro">6</div>
<div class="front-pro">7</div>
<div class="front-pro">8</div>
<div class="front-pro">9</div>
<div class="front-pro">10</div>
<div class="front-pro">11</div>
<div class="front-pro">12</div>
<div class="front-pro hidden">13</div>
<div class="front-pro hidden">14</div>
..... etc (200 divs more)
</div>
<div onclick="SearchNext();">next</div>

这是我的 javascript/jquery:

function SearchNext(){
var first = $('.inner-content').children('.front-pro:hidden:first');
first.prevAll(':lt(12)').hide();
first.nextAll(':lt(12)').show();
}

它会工作一次,然后停止工作。 (它会跳过数字 13)我希望每次单击“下一步”时都可以看到 12 个新元素,并隐藏前一个元素。

更新 - 这是我完美运行的最终结果 JSFIDDLE DEMO

感谢亚历克斯·查尔

PHP 用于创建页码,您也可以使用 javascript 来完成此操作

//$counter is search results
$x = 1;
$Pnumbers = '';
while($x <= ceil($counter/12)) {
if($x == 1){ $ecl = 'bold'; } else{ $ecl = ''; }
$Pnumbers .= ' <span class="number '.$ecl.' numbering" onClick="GoTo('.$x.');">'.$x.'</span> ';
$x++;
}

if($counter > 12){ echo'<div class="page-numbers">
<span class="prev number" onclick="GoTo(\'prev\')">Prev</span>
'.$Pnumbers.'
<span class="next number" onclick="GoTo(\'next\');">Next</span>
</div>'; }

Javascript:

function GoTo(nn) {
var nng = parseInt($('.page-numbers .numbering.bold').text());
if(nn == 'next'){
nn = nng+1;
}if(nn == 'prev'){
nn = nng-1;
}
//get all child elements with class front-pro
//of element with class .inner-content
var childElems = $(".inner-content .front-pro");
var totalpages = Math.ceil(childElems.length/12);
//iterate through the elements
var first = (nn-1)*12;
var last = first+11;
childElems.each(function(i, el) {

//show the elements that match the criteria removing css class
if (i >= first && i <= last) {
$(el).removeClass('hidden');
} else {
//hide rest
$(el).addClass('hidden');
}
});

if(nn > 1){ $('.page-numbers .prev').show(); }else{ $('.page-numbers .prev').hide(); }
if(nn < totalpages){ $('.page-numbers .next').show(); }else{ $('.page-numbers .next').hide(); }
$('.page-numbers .numbering').removeClass('bold');
$('.page-numbers .numbering:eq('+(nn-1)+')').addClass('bold');
}

CSS:

.front-pro.hidden{ display:none !important; }
.prev { display: none; }
.page-numbers .number{
background: #ff0000; }
.page-numbers{ text-align:center; }
.page-numbers .number.bold{ font-weight:bold; background:#000; }
.page-numbers .number:hover{ background:#000; cursor: pointer; }

确保前 12 个 div 不包含“hidden”类,后面的所有 div 都应该在该类中包含“hidden”

最佳答案

我对实现进行了一些更改以支持和以前的。我使用 css 类来隐藏内容。

function searchNext() {
$('.inner-content').children('.front-pro:lt(12)').addClass('hidden');
$('.inner-content').children('.front-pro:gt(11)').removeClass('hidden');
$(".next").hide();
$(".prev").show();
}

function searchPrev() {
$('.inner-content').children('.front-pro:lt(12)').removeClass('hidden');
$('.inner-content').children('.front-pro:gt(11)').addClass('hidden');
$(".next").show();
$(".prev").hide();
}
.front-pro.hidden {
display: none;
}
.prev {
display: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="inner-content">
<div class="front-pro">1</div>
<div class="front-pro">2</div>
<div class="front-pro">3</div>
<div class="front-pro">4</div>
<div class="front-pro">5</div>
<div class="front-pro">6</div>
<div class="front-pro">7</div>
<div class="front-pro">8</div>
<div class="front-pro">9</div>
<div class="front-pro">10</div>
<div class="front-pro">11</div>
<div class="front-pro">12</div>
<div class="front-pro hidden">13</div>
<div class="front-pro hidden">14</div>
</div>
<div class="next" onclick="searchNext();">next</div>
<div class="prev" onclick="searchPrev();">prev</div>

在您对下一个和上一个进行评论后,我创建了一个通用解决方案(我使用步骤 3 进行演示,但您可以使用您想要的任何内容):

var pager = (function() {
/*declare private variables*/
var first = 0,
last = 2,
step = 3;

function searchNext() {
//next function
//increasing first and last variables
first += step;
last += step;
pagerHelper();
}

function searchPrev() {
//previous function
//decrease first and last variables
first -= step;
last -= step;
pagerHelper();
}

function pagerHelper() {
//get all child elements with class front-pro
//of element with class .inner-content
var childElems = $(".inner-content .front-pro");
//iterate through the elements
childElems.each(function(i, el) {
//show the elements that match the criteria removing css class
if (i >= first && i <= last) {
$(el).removeClass('hidden');
} else {
//hide rest
$(el).addClass('hidden');
}
});
nextPreviousToggle(childElems.length);
}

function nextPreviousToggle(maxEle) {
//here the code is to show/hide next/previous buttons
if (last >= maxEle) {
$(".next").hide();
} else {
$(".next").show();
}
if (first === 0) {
$(".prev").hide();
} else {
$(".prev").show();
}
}
return {
searchNext: searchNext,
searchPrev: searchPrev
}
})();
.front-pro.hidden {
display: none;
}
.prev {
display: none;
}
.prev:hover,
.next:hover {
text-decoration: underline;
cursor: pointer;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="inner-content">
<div class="front-pro">1</div>
<div class="front-pro">2</div>
<div class="front-pro">3</div>
<div class="front-pro hidden">4</div>
<div class="front-pro hidden">5</div>
<div class="front-pro hidden">6</div>
<div class="front-pro hidden">7</div>
<div class="front-pro hidden">8</div>
<div class="front-pro hidden">9</div>
<div class="front-pro hidden">10</div>
<div class="front-pro hidden">11</div>
<div class="front-pro hidden">12</div>
<div class="front-pro hidden">13</div>
<div class="front-pro hidden">14</div>
</div>
<span class="next" onclick="pager.searchNext();">next</span>
<span class="prev" onclick="pager.searchPrev();">prev</span>

引用文献

:gt()

:lt()

关于javascript - Jquery 隐藏前 12 个元素,显示后 12 个元素,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36289573/

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