gpt4 book ai didi

javascript - 将 js 对象上的字段求和 2 个字段并创建而不是对象 javascript

转载 作者:行者123 更新时间:2023-12-01 02:27:23 26 4
gpt4 key购买 nike

我的目标是我每周收到一定数量的对象,这些对象上的每个对象都有日期、全名、总小时数和其他字段。我想按名称和每天的总小时数对这些对象数组进行排序。请仅使用 javascript,不要使用 jquery

对象示例

var anArray = [{
'End__c':"22:00",
'Id':"Q45575",
'Name':"W-299849",
'Resource_Full_Name__c':"test One",
'Start__c':"20:00",
'date__c':"2018-02-04",
'description__c':"rwqfrwe",
'total_hours__c':2
},{
'End__c':"21:00",
'Id':"Q45551",
'Name':"W-299809",
'Resource_Full_Name__c':"test Two",
'Start__c':"15:00",
'date__c':"2018-02-01",
'description__c':"rwqfrwe",
'total_hours__c':5
},{
'End__c':"20:00",
'Id':"Q45515",
'Name':"W-299849",
'Resource_Full_Name__c':"test One",
'Start__c':"10:00",
'date__c':"2018-02-04",
'description__c':"rwqfrwe",
'total_hours__c':2
}];

输出应该是这样的,假设星期日是 2/4

名称总计周日周一周二周三周五周六

测试一6 2 4 0 0 0 0 0

测试二 3 0 3 0 0 0 0 0

这就是我所拥有的

    var tmp = {}

results.workBlockList.forEach(function (item) {
var tempKey = item.Resource_Full_Name__c + item.date__c;
if (!tmp.hasOwnProperty(tempKey)) {
tmp[tempKey] = item;
} else {
tmp[tempKey].total_hours__c += item.total_hours__c;
}
});

不起作用,它只按日期和名称排序,而不给我只按日期排序的 2 个列表

最佳答案

您可以使用reduce功能。

看看这段代码

var items = [{
End__c:"22:00", Id:"Q45575",
Name:"W-299849", Resource_Full_Name__c:"test One", Start__c:"20:00",
date__c:"2018-02-04", description__c:"rwqfrwe", total_hours__c:2
},
{End__c:"13:00", Id:"A155645",
Name:"W-299849", Resource_Full_Name__c:"test One", Start__c:"9:00",
date__c:"2018-02-05", description__c:"rwqfrwe", total_hours__c:4
},
{
End__c:"19:00", Id:"A155645",
Name:"W-299849", Resource_Full_Name__c:"test Two", Start__c:"16:00",
date__c:"2018-02-05", description__c:"rwqfrwe", total_hours__c:3
}];

var result = items.reduce((a, c) => {
var targetDay = new Date(c.date__c).getDay() === 6 ? 0 :(new Date(c.date__c).getDay() + 1);

if (a[c.Resource_Full_Name__c]) {
a[c.Resource_Full_Name__c]['week'][targetDay] += c.total_hours__c;
a[c.Resource_Full_Name__c]['total'] += c.total_hours__c;
} else {
a[c.Resource_Full_Name__c] = { 'total': c.total_hours__c, 'week': new Array(7).fill(0) };
a[c.Resource_Full_Name__c]['week'][targetDay] = c.total_hours__c;
}

return a;
}, {});

result = Object.keys(result).map((k) => ({'workblock': {...result[k], ...{'resource': k}}}))

console.log(result);
.as-console-wrapper {
max-height: 100% !important
}

关于javascript - 将 js 对象上的字段求和 2 个字段并创建而不是对象 javascript,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48633390/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com