arrays - 赋值左侧的函数调用必须返回 Variant 或 Object，在两个数组中查找公共(public)值

Question

我有两个数组，我试图提取其中的公共(public)值，函数 findUniques 应该返回连接并用逗号分隔的字符串(它们是名称)。我想我很接近，但我找不到问题所在。第 10 行出现错误

Function findUniques(astrArray1() As String, astrArray2() As String) As String

    Dim blnMP5 As Boolean
    blnMP5 = False
    Dim counter1 As Long
    Dim counter2 As Long

    For counter1 = LBound(astrArray1) To UBound(astrArray1)
        For counter2 = LBound(astrArray1) To UBound(astrArray2)
            If astrArray1(counter1) = astrArray2(counter2) Then
                blnMP5 = False
                If blnMP5 = True Then
                    findUniques() = findUniques & "," & "astrArray1()"
                End If
            End If
        Next counter2
    Next counter1

End Function

Answer 1

您的错误在这一行:

findUniques() = findUniques & "," & "astrArray1()"

您正在尝试为函数调用分配一个值，这没有意义。

您应该在函数的开头声明一个变量并继续添加该变量并最终返回它:

Function findUniques(astrArray1() As String, astrArray2() As String) As String

    Dim blnMP5 As Boolean
    blnMP5 = False    
    Dim counter1 As Long
    Dim counter2 As Long  
    Dim uniquesString as String = ""

    For counter1 = LBound(astrArray1) To UBound(astrArray1)
        For counter2 = LBound(astrArray1) To UBound(astrArray2)
            If astrArray1(counter1) = astrArray2(counter2) Then
               blnMP5 = False
               If blnMP5 = True Then
                   uniquesString = uniquesString & "," & "astrArray1()"
               End If
             End If
        Next counter2
     Next counter1

End Function