python - 将列表中的 float 替换为 '0'

Question

所以我的编程作业希望我获取用户输入的数字、整数和 float 列表，然后按降序对它们进行排序，并将任何 float 替换为“0”。我已经完成了重新订购部分，但替换让我迷失了。

阅读数字编写一个程序，要求用户输入几个整数同一行，由垂直条分隔，周围有零个或多个空格(例如，“|”或“|”或“|”或“|”)。然后程序将显示输入的数字按降序排列(从最大到最小)，全部在同一行，用竖线和空格(“| ”)分隔。如果命令行上的任何条目都不是整数，程序应将其替换为 0。仅使用“for”循环或列表推导式。使用异常处理。

# takes input and split them to get a list
numbers = input("Please enter numbers separated by vertical bars '|' : 
").split("|")
# replace the floating numbers with "0"
for number in numbers:
    print(type(number))
    if number.isdigit() == False:
        numbers.replace(number,'0')
# takes the list and reverse order sort and prints it with a "|" in between
numbers.sort(key = float , reverse = True)
[print(number,end = ' | ') for number in numbers]

Answer 1

我所做的一项更改是将所有 for number in Numbers 切换为 for i in range(len(numbers))。这允许您通过索引访问实际变量，而对于数字中的数字仅获取值。

这是我的解决方案。我尝试添加评论来解释我这样做的原因，但如果您有任何疑问，请发表评论:

# takes input and split them to get a list
numbers = input("Please enter numbers separated by vertical bars '|'\n").split(
    "|")

# strip any extra spaces off the numbers
for i in range(len(numbers)):
    numbers[i] = numbers[i].strip(" ")

# replace the floating numbers and strings with "0"
for i in range(len(numbers)):
    try:
        # check if the number is an int and changes it if it is
        numbers[i] = int(numbers[i])
    except:
        # set the item to 0 if it can't be converted to a number
        numbers[i] = 0

# takes the list and reverse order sort and prints it with a "|" in between
numbers.sort(reverse = True)

# changes the numbers back into strings
numbers = [str(numbers[i]) for i in range(len(numbers))]
# makes sure that there are more than one numbers before trying
# to join the list back together
if len(numbers) > 1:
    print(" | ".join(numbers))
else:
    print(numbers[0])