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python - Pandas:应用函数:TypeError:不支持的操作数类型 -: 'unicode' 和 'unicode'

转载 作者:行者123 更新时间:2023-12-01 02:23:04 25 4
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我有以下数据框df:

name    event_time
------------------------------------------
Mary [(S, 2017-12-03T03:40:20.000Z), (V, 2017-12-07T02:51:32.000Z)]
Peter [(S, 2017-11-02T01:11:10.000Z), (V, 2017-11-19T07:23:12.000Z)]
Andy [(S, 2017-12-01T10:31:15.000Z), (V, 2017-12-09T12:31:10.000Z)]

然后,我使用以下代码来查找 event_time 字段中两个元素的持续时间:

df['duration'] = df.event_time.apply(lambda x:x[1][1]-x[0][1])

但是,我遇到了以下错误:

TypeError unsupported operand type(s) for -: 'unicode' and 'unicode' 
TypeErrorTraceback (most recent call last)
<ipython-input-7-7a191c6f2678> in <module>()
----> 1 df['duration'] = df.event_time.apply(lambda x:x[1][1]-x[0][1])

/opt/conda/envs/python2/lib/python2.7/site-packages/pandas/core/series.py in apply(self, func, convert_dtype, args, **kwds)
2218 else:
2219 values = self.asobject
-> 2220 mapped = lib.map_infer(values, f, convert=convert_dtype)
2221
2222 if len(mapped) and isinstance(mapped[0], Series):

pandas/src/inference.pyx in pandas.lib.map_infer (pandas/lib.c:62658)()

<ipython-input-7-7a191c6f2678> in <lambda>(x)
----> 1 df['duration'] = df.event_time.apply(lambda x:x[1][1]-x[0][1])

TypeError: unsupported operand type(s) for -: 'unicode' and 'unicode'

知道我在这里做错了什么吗?谢谢!

最佳答案

我相信您需要通过str[]选择值,转换to_datetime并减去:

s1 = pd.to_datetime(df['event_time'].str[1].str[1])
s2 = pd.to_datetime(df['event_time'].str[0].str[1])
df['duration'] = s1 - s2
print (df)
name event_time duration
0 Mary [(S, 2017-12-03T03:40:20.000Z), (V, 2017-12-07... 3 days 23:11:12
1 Peter [(S, 2017-11-02T01:11:10.000Z), (V, 2017-11-19... 17 days 06:12:02
2 Andy [(S, 2017-12-01T10:31:15.000Z), (V, 2017-12-09... 8 days 01:59:55

关于python - Pandas:应用函数:TypeError:不支持的操作数类型 -: 'unicode' 和 'unicode',我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47747703/

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