javascript - AJAX - 使用 AJAX 将 knockout 可观察值作为 JSON 对象发送到服务器

Question

我正在尝试以 JSON 对象的形式将绑定(bind)到特定可观察对象的表单字段发送到我的服务器，但我在服务器端收到空的 JSON 字符串。我不想发送整个 View 模型来完成此任务。这是我到目前为止的 JavaScript:

 $(document).ready(function(){
    ko.applyBindings(new AddSubjectKo());
});



  function AddSubjectKo()
  {
    var self=this;
    self.name = ko.observable();
    self.quiz = ko.observable();
    self.ass = ko.observable();
    self.oht = ko.observable();
    self.sess = ko.observable();
    self.ese = ko.observable();
    self.SubjectAdded=function()
    {
        $.ajax({
            url: "api/courses",
            type: "post",
            data: formToJSON(),
            contentType: "application/json",
            success: function(data){
           alert("success");
             },
          error:function(jqXHR, textStatus, errorThrown) {
               alert("failure");
             }   
       });  
        function formToJSON() {
            alert(self.name());
               return JSON.stringify({
                   "name": self.name,
                   "quiz": self.quiz,
                   "ass": self.ass,
                   "oht": self.oht,
                   "sess": self.sess,
                   "ese": self.ese,
                    });
           }
        }
      //$("#alert").slideDown();

  }

Answer 1

您可以使用ko.toJSON函数来实现:

  function AddSubjectKo()
  {
    var self=this;
    self.name = ko.observable();
    self.quiz = ko.observable();
    self.ass = ko.observable();
    self.oht = ko.observable();
    self.sess = ko.observable();
    self.ese = ko.observable();
    self.SubjectAdded=function()
    {
        $.ajax({
            url: "api/courses",
            type: "post",
            data: ko.toJSON(self),
            contentType: "application/json",
            success: function(data){
                alert("success");
             },
             error:function(jqXHR, textStatus, errorThrown) {
                alert("failure");
             }   
       });  
   }