django - 在 DefaultRouter 的根 api View 上订购项目

Question

我正在使用 DRF 提供的 DefaultRouter，因为我需要一个根 api View 。但是，该 View 上的项目没有任何逻辑顺序。我查看了源代码，发现每个条目都被放入字典中(本质上没有排序)。

class DefaultRouter(SimpleRouter):
    """
    The default router extends the SimpleRouter, but also adds in a default
    API root view, and adds format suffix patterns to the URLs.
    """
    include_root_view = True
    include_format_suffixes = True
    root_view_name = 'api-root'

    def get_api_root_view(self):
        """
        Return a view to use as the API root.
        """
        api_root_dict = {}
        list_name = self.routes[0].name
        for prefix, viewset, basename in self.registry:
            api_root_dict[prefix] = list_name.format(basename=basename)

        class APIRoot(views.APIView):
            _ignore_model_permissions = True

            def get(self, request, format=None):
                ret = {}
                for key, url_name in api_root_dict.items():
                    ret[key] = reverse(url_name, request=request, format=format)
                return Response(ret)

        return APIRoot.as_view()

我想按字母顺序对根 api View 上的项目进行排序，并且可以通过修改源轻松实现。但我想知道，你们有没有想过在不修改源代码的情况下订购根 api 项目的解决方案？

Answer 1

根据您的建议和 Denis Cornehi 答案中的第一点，这是 DefaultRouter 的扩展，它按 base_names 对 url 进行排序:

# myapp/routers.py

from rest_framework import routers
from rest_framework import views
from rest_framework.response import Response
from rest_framework.reverse import reverse
import operator
import collections


class OrderedDefaultRouter(routers.DefaultRouter):

    def get_api_root_view(self):
        """
        Return a view to use as the API root but do it with ordered links.
        """
        api_root_dict = {}
        list_name = self.routes[0].name
        for prefix, viewset, basename in self.registry:
            api_root_dict[prefix] = list_name.format(basename=basename)

        class APIRoot(views.APIView):
            _ignore_model_permissions = True

            def get(self, request, format=None):
                ret = {}
                for key, url_name in api_root_dict.items():
                    ret[key] = reverse(url_name, request=request, format=format)
                sorted_ret = collections.OrderedDict(sorted(ret.items(), key=operator.itemgetter(0)))
                return Response(sorted_ret)

        return APIRoot.as_view()