python套接字错误: AF_INET address must be tuple,不是str

Question

我有这个简短的程序:

import sys
import socket

target = "google.co.uk"
port = 443
print(target)

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect(target)
print("successfull connection to: " + target)

当我运行代码时，我得到:

    s.connect(target)
TypeError: getsockaddrarg: AF_INET address must be tuple, not str

当我尝试将该行更改为:s.connect(target,443)我也遇到了一个错误:

    s.connect(target,443)
TypeError: connect() takes exactly one argument (2 given)

问题是什么？

Answer 1

函数接收的参数是一个元组，因此应该将元组作为参数给出。意思是 f(a,b) 使用 f((a,b))

调用函数

因此，我们像这样修复您的代码:

import sys
import socket

target = "google.co.uk"
port = 443
print(target)

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((target, port))
print("successfull connection to: " + target)