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javascript - 如何从 Promise 返回 Observable

转载 作者:行者123 更新时间:2023-12-01 02:07:21 24 4
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我需要从 Promise 返回 Observable,但是当我尝试学习 Angular 时,我被语法所困扰。所以事情是这样的:

我有一个以下函数 getCountries(这是由另一个实用程序订阅的),我需要调用它来检索国家/地区列表。“lang”尚未定义。我添加它只是为了完成我的 api 的 url。

getCountries(): Observable<Country[]> {
if (this.countries) {
return Observable.of(this.countries);
} else if (this.countriesObservable) {
return this.countriesObservable;
} else {
//lang is not defined yet it has to be retrieved from storage

this.countriesObservable = this.http.get(AppSettings.API_URL + '?locale=' + lang).map(json => {
delete this.countriesObservable; // when the cached countries is available we don't need reference anymore
this.countries = json as Country[];
this.countries = this.countries.sort(function (a, b) { return (a.Name > b.Name) ? 1 : ((b.Name > a.Name) ? -1 : 0); });
return this.countries;
}).share();
return this.countriesObservable;
}
}

由于 api 需要语言(lang),并且此信息存储在存储中,可以按如下方式从存储中检索:

  this.storage.get(AppSettings.STORAGE_KEYS.LANGUAGE_APP).then(language=>{
//here I can use language
});

现在我遇到的问题是如何在从上述 promise 中检索语言信息后调用我的 api。我需要确保函数(getCountries)仍然返回它最初返回的可观察值。感谢您的帮助。

有些人建议将它们包装在 Observable.fromPromise 中,我也这样做了,但这破坏了代码。我一定错过了一些我知道的东西。这里是:是否错过了返回某些内容,在之后发布我的堆栈跟踪代码:

 getCountries(): Observable<Country[]> {
if (this.countries) {
return Observable.of(this.countries);
} else if (this.countriesObservable) {
return this.countriesObservable;
} else {
Observable.fromPromise(this.storage.get(AppSettings.STORAGE_KEYS.LANGUAGE_APP)).subscribe(language=>{
//here I can use language
this.countriesObservable = this.http.get(AppSettings.API_URL + '?locale=' + language).map(json => {
delete this.countriesObservable;
this.countries = json as Country[];
this.countries = this.countries.sort(function (a, b) { return (a.Name > b.Name) ? 1 : ((b.Name > a.Name) ? -1 : 0); });
return this.countries;
}).share();
return this.countriesObservable;
});
}
}



Error: Uncaught (in promise): TypeError: Cannot read property 'subscribe' of undefined
TypeError: Cannot read property 'subscribe' of undefined
at http://localhost:8100/build/main.js:71:33
at new t (http://localhost:8100/build/polyfills.js:3:20886)
at UtilsProvider.webpackJsonp.10.UtilsProvider.getCountryById (http://localhost:8100/build/main.js:70:16)
at MyApp.webpackJsonp.851.MyApp.updateUserInfo (http://localhost:8100/build/main.js:10067:47)
at http://localhost:8100/build/main.js:9774:23
at SafeSubscriber.schedulerFn [as _next] (http://localhost:8100/build/vendor.js:4004:36)
at SafeSubscriber.__tryOrUnsub (http://localhost:8100/build/vendor.js:16987:16)
at SafeSubscriber.next (http://localhost:8100/build/vendor.js:16934:22)
at Subscriber._next (http://localhost:8100/build/vendor.js:16874:26)
at Subscriber.next (http://localhost:8100/build/vendor.js:16838:18)
at c (http://localhost:8100/build/polyfills.js:3:19132)
at c (http://localhost:8100/build/polyfills.js:3:18841)
at http://localhost:8100/build/polyfills.js:3:19613
at t.invokeTask (http://localhost:8100/build/polyfills.js:3:15040)
at Object.onInvokeTask (http://localhost:8100/build/vendor.js:4238:33)
at t.invokeTask (http://localhost:8100/build/polyfills.js:3:14961)
at r.runTask (http://localhost:8100/build/polyfills.js:3:10214)
at o (http://localhost:8100/build/polyfills.js:3:7274)
at e.invokeTask [as invoke] (http://localhost:8100/build/polyfills.js:3:16203)
at p (http://localhost:8100/build/polyfills.js:2:26993)

最佳答案

只需使用 Observable.fromPromise。所以在你的情况下,它会是

getCountries(): Observable<Country[]> {
if (this.countries) {
return Observable.of(this.countries);
} else if (this.countriesObservable) {
return this.countriesObservable;
} else {
return Observable.fromPromise(this.storage.get(AppSettings.STORAGE_KEYS.LANGUAGE_APP)).mergeMap(language=>{
//here I can use language
this.countriesObservable = this.http.get(AppSettings.API_URL + '?locale=' + language).map(json => {
delete this.countriesObservable; // when the cached countries is available we don't need the reference anymore
this.countries = json as Country[];
this.countries = this.countries.sort(function (a, b) { return (a.Name > b.Name) ? 1 : ((b.Name > a.Name) ? -1 : 0); });
return this.countries;
}).share();
return this.countriesObservable;
});
}
}

关于javascript - 如何从 Promise 返回 Observable,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50007305/

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