jquery - 将值传递给 jquery 对话框表单

Question

我需要一个对话框窗口来弹出一个表单并将值传递给该表单。我尝试了多种方法来解决这个问题，但一直未能成功。我到处寻找，似乎没有任何效果。

这是我最近的尝试:

  var message="variable";

 .click(function() {
 $( "#dialog-form" ).dialog( "open" );
 $('<input>').attr({
    type: 'text',
    id: 'hidden-input",
    value: message,
    name: 'bar'
 }).appendTo("#dialog-form");

如果我将附加内容放入对话框中，弹出窗口将停止工作(我想我不知道如何正确执行此操作)

Answer 1

我完全使用脚本来处理对话框(我认为它更干净):

http://jsfiddle.net/fE6q2/

html:

Default firstname:<br>
<input type='text' id="default_firstname"/>
<br><br>
<button onclick='on_create_form_clicked()'>create form</button>

JavaScript:

function on_create_form_clicked()
{
    var html =
       "<div>" +
          "Firstname:<br>" +
          "<input type='text' class='firstname'/>" +
          "<br/><br/>" +
          "Lastname:<br>" +
          "<input type='text' class='lastname'/>" +
          "<br/><br/>" +
          "<button class='ok'>ok</button>" +    
       "</div>";

    var div = $(html);

    var default_firstname = $('#default_firstname').val();
    div.find('.firstname').val(default_firstname);        

    div.find('.ok').click(function()
    {
        div.dialog('close');

        var firstname = div.find('.firstname').val();
        var lastname = div.find('.lastname').val();

        alert("firstname was " + firstname
            + " and lastname was " + lastname);        
    });

    div.dialog(
    {
        title:"Enter firstname and lastname",
        close: destroy_this_dialog
    });
}

function destroy_this_dialog(event, ui)
{
  $(this).dialog("destroy");
  $(this).remove();
}