python - 根据计数器值对列表进行排序

Question

如何根据 Counter 对象的值对 Python 列表进行排序？

c = Counter({"a": 1, "b": 6, "c":19})
l = ["b", "c", "a"]

# after sorting based on counter values
l = ["c", "b", "a"]

Answer 1

sorted()采用如下关键函数:

代码:

sorted(l, key=lambda x: -c[x])

或就地为:

l.sort(key=lambda x: -c[x])

测试代码:

from collections import Counter

c = Counter({"a": 1, "b": 6, "c": 19})
l = ["b", "c", "a"]

# after sorting based on counter values
l = ["c", "b", "a"]

print(sorted(l, key=lambda x: -c[x]))

结果:

['c', 'b', 'a']