javascript - 比较数组并删除对象

Question

下面有这段代码，我试图通过比较图表来删除整行{"id": "Apple", "group": 1}使用 testArray 查看 graph 与 testArray 共有的每个对象，只需删除整行即可。但我不太确定如何完成删除它任何帮助将不胜感激

var graph = {   "nodes": [
    {"id": "Apple", "group": 1},
    {"id": "Cherry", "group": 2},
    {"id": "Tomato", "group": 3}
    ],
    "links": [
    {"source": "Apple", "target": "Cherry", "value": 1},
    {"source": "Cherry", "target": "Tomato", "value": 1},
    {"source": "Tomato", "target": "Apple", "value": 1}
    ]
    };

    var testArray = ['Apple'];

    var nodes = graph["nodes"];
    let removeNodes = nodes;
    removeNodes.forEach((obj) => {
        if (testArray.includes(obj.id.toString())) 
    });

Answer 1

如何循环 testArray 并找到节点数组中的每个项目并将其删除？

编辑:如果您想通过给定键删除，您可以创建一个接受对象键和列表的函数。

var graph = {
  nodes: [
    {
      id: "Apple",
      group: 3
    },
    {
      id: "Cherry",
      group: 3
    },
    {
      id: "Tomato",
      group: 3
    },
    {
      id: "Lemon",
      group: 4
    },
    {
      id: "Grape",
      group: 5
    }
  ],
  links: [
    {
      source: "Apple",
      target: "Cherry",
      value: 1
    },
    {
      source: "Cherry",
      target: "Tomato",
      value: 1
    },
    {
      source: "Tomato",
      target: "Apple",
      value: 1
    },
    {
      source: "Lemon",
      target: "Grape",
      value: 1
    },
    {
      source: "Grape",
      target: "Lemon",
      value: 1
    }
  ]
};

function removeObject(key, arr) {
  arr.forEach((item) => {
    // get all nodes that has the value of item
    const foundNodes = graph.nodes.filter(node => arr.includes(node[key]));
    // get index of each found item
    foundNodes.forEach((node) => {
      const nodeIndex = graph.nodes.indexOf(node);
      // remove item by index
      graph.nodes.splice(nodeIndex, 1);
    })
  });
}


// find object by group
removeObject('group', [3]);
console.log(graph);