javascript - 错误 : Actions must be plain objects. 使用自定义中间件进行异步操作。 React-redux 错误

Question

index.js

import store from "./store";
import { createStore } from 'redux';
import reducers from './reducers';
import { Provider } from 'react-redux';


console.log('init state', store.getState());

ReactDOM.render(    
    <Provider store={ store }>
        <App />
    </Provider>, 
    document.getElementById('root')
);

registerServiceWorker();

action.js

import * as types from "./types";
import axios from 'axios';
import { incrementProgress, decrementProgress } from "./progress";


const userLogin = username => ({
  type: types.AUTH_LOGIN,
  username,
});

const userLogout = () => ({
  type: types.AUTH_LOGOUT,
});

const fakeLoginRequest = (username, password) => {
    alert(username, password)
}

export const doLogin = username => {
    alert(username)
};

export const doLogout = () => dispatch => {
  dispatch(userLogout());
};

LoginForm.jsx - dumb组件

class LoginForm extends React.Component {

    constructor(props) {
        super(props);
        this.state = {
            username: '',
            password: '',
        };

        this.handleClick = this.handleClick.bind(this);
    }

    fakeLogin = e => {
        const { username } = this.state;
        e.preventDefault();
        if (!username) {
          return alert("Provide a username.");
        }
        this.props.doLogin(username);
        this.setState({ username: "" });
      };

    render() {

        return (
            <div>
            <MuiThemeProvider>
              <div>
               <TextField
                 hintText="Enter your Username"
                 floatingLabelText="Username"
                 onChange = {(event,newValue) => this.setState({username:newValue})}
                 />
               <br/>
                 <TextField
                   type="password"
                   hintText="Enter your Password"
                   floatingLabelText="Password"
                   onChange = {(event,newValue) => this.setState({password:newValue})}
                   />
                 <br/>
                 <RaisedButton label="Submit" primary={true} style={style} onClick={this.fakeLogin}/>
             </div>
             </MuiThemeProvider>
          </div>
    );
}
}   

export default LoginForm;

LoginPage.jsx - Wise 组件

const LoginPage = ({ auth, doLogin, doLogout }) => (

    <div>

      <NavBar/>
        <div className="row">
            <div style={{display: 'flex', justifyContent: 'center'}} className="col-md-4 col-md-offset-4">
                <LoginForm doLogin={doLogin} doLogout={doLogout} auth={auth} />
            </div>
        </div>
      </div>

);
const mapStateToProps = state => ({
  auth: state.auth,
});

export default connect(mapStateToProps, { doLogin, doLogout })(LoginPage);

我对react-redux完全陌生，我正在尝试创建一个识别用户当前登录状态的流程。我尝试使用上面的代码是为了确保用户名和密码正确通过并提醒他们。

但是，我收到错误

错误:操作必须是普通对象。使用自定义中间件进行异步操作。 React-redux 错误。

在 LoginForm.jsx 的 this.props.doLogin(username); 上。看起来它也与按钮的onClick有关。我不明白，因为我调用的函数不是异步的。

我做错了什么？

Answer 1

就像错误所示，您的操作创建者必须返回一个对象。

export const doLogin = username => {
    console.log('READ THE DOCS. IT IS VERY HELPFUL TO READ THE DOCS.');
    console.log(username);
    return {
        type: 'YOUR_ACTION_TYPE',
        payload: { whatever: 'you', want: 'it', to: 'be' }
    };
};