javascript - 比较两个对象数组与键，如果没有找到，则将其添加到数组中

Question

array1 =  [
    {id: 1, height: 178}, {id: 1, height: 176},
    {id: 2, height: 168},{id: 2, height: 164}
]

array2 =  [
    {id: 1, height: ''},{id: 1, height: ''},
    {id: 2, height: ''},{id: 2, height: ''}, 
    {id: 3, height: ''}, {id: 3, height: ''}, 
    {id: 4, height: ''}, {id: 4, height: ''}
]

resultArray  = [
    {id: 1, height: 178},{id: 1, height: 176},
    {id: 2, height: 168},{id: 2, height: 164}, 
    {id: 3, height:''}, {id: 3, height: ''}, 
    {id: 4, height: ''}, {id: 4, height: ''}
]

我希望将 array1 的 id 与 array2 的 id 进行比较，如果 array1 中缺少任何对象，那么我们将其添加到该对象中大批。你能告诉我该怎么做吗？

谢谢

Answer 1

我建议使用一组 array1 的键来进行快速查找。请注意，这会改变 array1:

const array1 = [{id: 1, height: 178},{id: 1, height: 176},{id: 2, height: 168},{id: 2, height: 164}]
const array2 = [{id: 1, height: ''},{id: 1, height: ''},{id: 2, height: ''},{id: 2, height: ''}, {id: 3, height: ''}, {id: 3, height: ''}, {id: 4, height: ''}, {id: 4, height: ''}]

const ids = new Set(array1.map(e => e.id));

array2.forEach(e => {
  if (!ids.has(e.id)) {
    array1.push(e);
  }
});

console.log(array1);