python:如何从列表中打印单独的行？

Question

这是我的代码:

class Message:

    def __init__(self,sender,recipient):
        self.sender = sender
        self.recipient = recipient
        self.wishList = []

    def append(self,line):
        self.wishList.append(str(line))
        for i in line:
            return i

    def toString(self):
        return 'From:{}\nTo:{}\n{}'.format(self.sender,self.recipient,
                                           self.wishList)

输出是:

From:Aria

To:Santa

['For Christmas, I would like:', 'Video games', 'World peace']

如何分隔行并使输出如下？

From:Aria

To:Santa

For Christmas, I would like:

Video games

World peace

Answer 1

您可以通过"joinerchar".join(list)将列表转换为字符串。在您的代码中它将是这样的。

return 'From:{}\nTo:{}\n{}'.format(self.sender,self.recipient,
                                       "\n".join(self.wishList))