python - 将字符串拆分为多个字符 - Python

Question

我有一个字符串:

V51M229D180728T132714_ACCEPT_EC_NC

这需要分成

String 1 : V51 (Can be variable but always ends before M)
String 2 : M22 (Can be variable but always ends before D)
String 3 : D180728 (Date in YYMMDD format)
String 4 : 132714 (Timestamp in HHMMSS format)
String 5 : ACCEPT (Occurs between "_")
String 6 : EC (Occurs between "_")
String 7 : NC (Occurs between "_")

我是Python新手，希望能得到一些帮助。

谢谢。

Answer 1

使用re模块:

import re
a = 'V51M229D180728T132714_ACCEPT_EC_NCM'
re.search('(\w+)(M\w+)(D\d+)(T\d+)_(\w+)_(\w+)_(\w+)', a).groups()

您将得到:

('V51', 'M229', 'D180728', 'T132714', 'ACCEPT', 'EC', 'NCM')