python - 如何修复随机选择生成器？

Question

我的 python 游戏无法运行，序列开头为:

if int(total_time) > 10:   

没有触发，但是当我按 D、C 或 W 时，我收到“你打开了一些东西”文本。据我所知，那里的代码是正确的，只是不起作用。我使用了 或 prevtime 来允许您第一次执行此操作。

import random, time, pygame, sys
from pygame.locals import *
total_time = time.clock()
pygame.init()
XQR_prevtime = 0
ppayh_prevtime = 0
pu_ekaw_prevtime = 0
diff = 1
windowSurface = pygame.display.set_mode((400,400),0,32)
time.sleep(3)
XQR_awakened = False
ppayh_awakened = False
pu_ekaw_awakened = False

    if int(total_time) > 10:

        if int(XQR_prevtime) > (12 - diff) or int(XQR_prevtime) == 0 or XQR_awakened == True:
            if XQR_awakened == True:
                print("You left something open...")
                time.sleep(2)
                print("And a mystery came in")
                time.sleep(2)
                sys.exit()
            if random.randint(0,diff) == 1:
                print(3)
                XQR_prevtime = time.clock()
                door_opening.play()
                XQR_awakened = True

        if int(ppayh_prevtime) > (12 - diff) or int(ppayh_prevtime) == 0 or ppayh_awakened == True:
            if ppayh_awakened == True:
                print("You left something open...")
                time.sleep(2)
                print("And a friend came in")
                time.sleep(2)
                sys.exit()
            if randint(0,diff) == 1:
                print(3)
                ppayh_prevtime = time.clock()
                closet_opening.play()
                ppayh_awakened = True

        if int(pu_ekaw_prevtime) > (12 - diff) or int(pu_ekaw_prevtime) == 0 or pu_ekaw_prevtime == True:
            if ekaw_up_awakened == True:
                print("You left something open...")
                time.sleep(2)
                print("And an answer came in")
                time.sleep(2)
                sys.exit()
            if randint(0,diff) == 1:
                print(3)
                pu_ekaw_prevtime = time.clock()
                window_opening.play()
                pu_ekaw_awakened = True

Answer 1

total_time 永远不会改变，因此您永远无法达到您的条件。

线路

total_time = time.clock()

为total_time分配一个数值(float)。没有对 time.clock() 函数的引用，该函数仅返回一个普通的浮点对象，而不是计时器对象。

普通的float值不会改变，它们是不可变的。 total_time 值不会随着游戏运行而改变。

如果你想测量耗时，只需继续调用time.clock():

if time.clock() > 10:

此处不需要将浮点值转换为 int，与整数进行比较即可。