javascript - XMLHTTPRequest 未收到来自 LotusScript 代理的响应

Question

我有一个 LotusScript 代理，末尾有以下代码

Set nam = session.Createname(respParty)
Print "Content-type: text/plain"
Print nam.Abbreviated

我有一个 JavaScript 按钮，其中在 Submit() 之前包含以下内容

    var noEmployees = document.getElementById('NoEmployees').value;
    var stateName = document.getElementById('State').value;
    var url = 'http://' + window.location.host + '/ebsprospects.nsf/GetResponsiblePerson?OpenAgent&NoEmployees=' + noEmployees + '&State=' + stateName;     
    var xhttp = new XMLHttpRequest();
    xhttp.open("GET", url);

    xhttp.onreadystatechange = function() {
    if (this.readyState == 4 && this.status == 200) {           
        }
    };
    alert (xhttp.responseText);
    document.getElementById("ResponsibleParty").innerHTML = xhttp.responseText;

一切正常，除了返回空白值。

如果我输入网址:

http://[webaddress]/[dbname].nsf/GetResponsiblePerson?OpenAgent&NoEmployees=20&State=IL

进入浏览器，就像我将其传递到它返回的 JS 代码中一样:

    X Content-type: text/plain Susanne Anderson/CBS

我做错了什么？

我的 JS 代码顺序是否错误？

Answer 1

 var noEmployees = document.getElementById('NoEmployees').value;
    var stateName = document.getElementById('State').value;
    var url = 'http://' + window.location.host + '/ebsprospects.nsf/GetResponsiblePerson?OpenAgent&NoEmployees=' + noEmployees + '&State=' + stateName;     
    var xhttp = new XMLHttpRequest();
    xhttp.open("GET", url);

    xhttp.onreadystatechange = function() {
    if (this.readyState == 4 && this.status == 200) {          
         alert (xhttp.responseText);
         document.getElementById("ResponsibleParty").innerHTML = xhttp.responseText;
        }
    };
    xhttp.send();

希望这会有所帮助。