javascript - 创建一个数组对象及其相应的获胜者

Question

假设我有一个数组:

let array = [
  { win: "Ali", loser: "Jake"},
  { win: "carl", loser: "Dean"},
  { win: "Eli", loser: "Jake"},
  { win: "Eli", loser: "carl"},
  { win: "Ali", loser: "carl"},
  { win: "carl", loser: "Dean"},
  { win: "Dean", loser: "Eli"}
];

输出应该是:

{
  'Ali': ['Jake', 'carl'],
  'Jake':   [],
  'carl': ['Dean'],
  'Dean':  ['eli'],
  'eli': ['Jake', 'carl'],
}

所以我的第一步是在对象内创建一个包含所有获胜者的空数组。然后将获胜者的每个元素与其相应的失败者一起插入。但我对这种方法有点迷失。我有什么:

function winner(array) {
  let newObj = {};

  for (let obj of array) {
    newObj[obj.winner] = [];
  }
}

Answer 1

let array = [
  { win: "Ali", loser: "Jake"},
  { win: "carl", loser: "Dean"},
  { win: "Eli", loser: "Jake"},
  { win: "Eli", loser: "carl"},
  { win: "Ali", loser: "carl"},
  { win: "carl", loser: "Dean"},
  { win: "Dean", loser: "Eli"}
];

const result = {};
for (let obj of array) {
if(result[obj.win] && !result[obj.win].includes(obj.loser)){
    result[obj.win].push(obj.loser);
}
else{
    result[obj.win] = [obj.loser];
}
if(!result[obj.loser])
    result[obj.loser] = [];      
}
console.log(result);