javascript - 如何根据关键条件通过两个键对对象进行排序

Question

var obj = 
[{
    "distance": 7000,
    "rating": 2,
    "name": 'a'
},
{
    "distance": 3470,
    "rating": 1,
    "name": 'b'
}, {
    "distance": 3470,
    "rating": 2,
     "name": 'c'
}, {
    "distance": 3480,
    "rating": 5,
    "name": 'd'
}, {
    "distance": 3490,
    "rating": 3,
    "name": 'e'
}, {
    "distance": 4000,
    "rating": 3,
    "name": 'f'
}];

我希望获得按距离排序的输出，如果距离彼此接近某个值(例如10)，则按评级排序。

我尝试了很多方法，但没有任何效果。

 obj.sort(function(a, b) {
     return (a["distance"] - b["distance"]);
 });

 obj.sort(function(a, b) {
    return (b["distance"] - a["distance"] <= 10 ? 0: 1) || b["rating"] - 
    a["rating"];
 });

在上面的代码中，首先我尝试按距离排序，然后如果距离差小于 10，我会按评分排序。但这不能正常工作。

JSBin 链接 - https://jsbin.com/nawiderebu/edit?html,js,console

我想得到如下输出:

[
{
    "distance": 3470,
    "rating": 2,
     "name": 'c'
},{
    "distance": 3470,
    "rating": 1,
    "name": 'b'
}, {
    "distance": 3480,
    "rating": 5,
    "name": 'd'
}, {
    "distance": 3490,
    "rating": 3,
    "name": 'e'
}, {
    "distance": 4000,
    "rating": 3,
    "name": 'f'
},{
    "distance": 7000,
    "rating": 2,
    "name": 'a'
}
]

Answer 1

使用Math.abs(a["distance"] - b["distance"] < 10)状况如下。你不需要有第二个 sort打电话。

var obj = [
    {
        "distance": 7000,
        "rating": 2,
        "name": 'a'
    },
    {
        "distance": 3470,
        "rating": 1,
        "name": 'b'
    }, {
        "distance": 3470,
        "rating": 2,
         "name": 'c'
    }, {
        "distance": 3480,
        "rating": 5,
        "name": 'd'
    }, {
        "distance": 3490,
        "rating": 3,
        "name": 'e'
    }, {
        "distance": 4000,
        "rating": 3,
        "name": 'f'
    }
]

obj.sort(function(a, b) {
    return Math.abs(a["distance"] - b["distance"]) <= 10 ? (b["rating"] - a["rating"]) : (a["distance"] - b["distance"]);
});

console.log(obj)