javascript - 如何在父类(super class)构造函数中初始化/设置值？在 typescript 中

Question

给定这两个类:

用户

    export class User {

        constructor(id?: string, userName?: string, fullName?: string,
 email?: string, jobTitle?: string, phoneNumber?: string, roles?: string[]) {
            this.id = id;
            this.userName = userName;
            this.fullName = fullName;
            this.email = email;
            this.jobTitle = jobTitle;
            this.phoneNumber = phoneNumber;
            this.roles = roles;
        }

    }

和从User扩展的UserEdit

import { User } from './user.model';


export class UserEdit extends User {
    constructor(currentPassword?: string, newPassword?: string, confirmPassword?: string) {
        super();

        this.currentPassword = currentPassword;
        this.newPassword = newPassword;
        this.confirmPassword = confirmPassword;
    }

    public currentPassword: string;
    public newPassword: string;
    public confirmPassword: string;

}

可以从UserEdit将email设置为空字符串''，从创建新对象？。例如。

let userEdit:UserEdit = new UserEdit()

Answer 1

您需要使用 super(param1, param2, param3, ...) 在基类中传递参数

就你的情况

super(id, userName, fullName, email, jobTitle, phoneNumber, roles);

super(id, username, fullname, '', jobTitle, phoneNumber, roles);