python - 在每行开头添加前缀不起作用

Question

我有一行脚本，它抓取目录和子目录中的所有 .blend 文件并将它们的路径写入文件中。我希望每一行都有一个起始前缀

"

但是这不起作用。当我在我也需要的行末尾添加前缀时，它会起作用。

for root, dirs, files in os.walk(cwd):
            for file in files:
                if file.endswith('.blend'):
                    with open("filepaths","a+") as f:
                        f.write(os.path.join('"', root, file, '",' "\n"))

此输出

/home/django/copypaste/cleanup/var/media/admin/94bbcd25-10a2-4ec2-bd83-a7cef0690320/splash279/splash279.blend/",
/home/django/copypaste/cleanup/var/media/admin/94bbcd25-10a2-4ec2-bd83-a7cef0690320/splash279/lib/props/barbershop_pole.blend/",
/home/django/copypaste/cleanup/var/media/admin/94bbcd25-10a2-4ec2-bd83-a7cef0690320/splash279/lib/props/hairdryer.blend/",
/home/django/copypaste/cleanup/var/media/admin/94bbcd25-10a2-4ec2-bd83-a7cef0690320/splash279/lib/chars/pigeon.blend/",
/home/django/copypaste/cleanup/var/media/admin/94bbcd25-10a2-4ec2-bd83-a7cef0690320/splash279/lib/chars/agent.blend/",
/home/django/copypaste/cleanup/var/media/admin/94bbcd25-10a2-4ec2-bd83-a7cef0690320/splash279/lib/nodes/nodes_shaders.blend/",
/home/django/copypaste/cleanup/var/media/admin/94bbcd25-10a2-4ec2-bd83-a7cef0690320/splash279/tools/camera_rig.blend/"，

但行首缺少第一个前缀 "

Answer 1

简单修复:

f.write(f'"{os.path.join(root, file)}",\n'))           # python 3.6+
f.write('"{}",\n'.format(os.path.join(root, file))))   # python 2.7+

测试:

import os

for root, dirs, files in os.walk("./"):
    for file in files:
        # if file.endswith('.blend'): # have no blends
        with open("filepaths","a+") as f:
            f.write(f'"{os.path.join(root, file)}",\n')            # 3.6
            f.write('"{}",\n'.format(os.path.join(root, file)))    # 2.7

with open("filepaths" ) as f:
    print(f.read())

输出(仅在目录中得到一个文件，将其写入文件两次(3.6 + 2.7)):

"./main.py",
"./main.py",

<小时/>

不知道为什么你的不起作用......这在 3.6 中有效:

import os
for i in range(5):
    with open(f"{i}.blend","w") as f:
        f.write(" ")
    with open(f"{i}.txt","w") as f:
        f.write(" ")

for root, dirs, files in os.walk("./"):
    for file in files:
        if file.endswith('.blend'):
            with open("filepaths","a+") as f:
                f.write(os.path.join('"', root, file, '",' "\n"))
        else:
            print("Not a blend: ", file)

with open("filepaths") as f:
    print(f.read())

输出:

Not a blend:  0.txt
Not a blend:  main.py
Not a blend:  1.txt
Not a blend:  4.txt
Not a blend:  3.txt
Not a blend:  2.txt
"/./3.blend/",
"/./2.blend/",
"/./4.blend/",
"/./1.blend/",
"/./0.blend/",