Python - 如何从文本中打印出一行

Question

所以我一直在使用 bs4 进行训练并设法打印出文本。现在我设法打印出 var ajaxsearch ，其中 init 的功能要多得多。

我编写了一段代码，它打印出所有包含 javascript 的内容，并打印出 var ajaxsearch 开头的位置:

  try:
        product_li_tags = bs4.find_all('script', {'type': 'text/javascript'})
    except Exception:
        product_li_tags = []

    special_code = ''
    for s in product_li_tags:
        if s.text.strip().startswith('var ajaxsearch'):
            special_code = s.text
            break

    print(special_code)

我得到的输出是:

var ajaxsearch = false;
var combinationsFromController ={
  "224114": {
    "attributes_values": {
      "4": "5.5"
    },
    "attributes": [
      22
    ],

    "unit_impact": 0,
    "minimal_quantity": "1",
    "date_formatted": "",
    "available_date": "",
    "id_image": -1,
    "list": "'22'"
  },
  "224140": {
    "attributes_values": {
      "4": "6"
    },
    "attributes": [
      23
    ],
    "unit_impact": 0,
    "minimal_quantity": "1",
    "date_formatted": "",
    "available_date": "",
    "id_image": -1,
    "list": "'23'"
  },
  "224160": {
    "attributes_values": {
      "4": "6.5"
    },
    "attributes": [
      24
    ],
    "unit_impact": 0,
    "minimal_quantity": "1",
    "date_formatted": "",
    "available_date": "",
    "id_image": -1,
    "list": "'24'"
  },
  "224139": {
    "attributes_values": {
      "4": "7"
    },
    "attributes": [
      25
    ],
    "unit_impact": 0,
    "minimal_quantity": "1",
    "date_formatted": "",
    "available_date": "",
    "id_image": -1,
    "list": "'25'"
  },
  "224138": {
    "attributes_values": {
      "4": "7.5"
    },
    "attributes": [
      26
    ],
    "unit_impact": 0,
    "minimal_quantity": "1",
    "date_formatted": "",
    "available_date": "",
    "id_image": -1,
    "list": "'26'"
  },
  "224113": {
    "attributes_values": {
      "4": "8"
    },
    "attributes": [
      27
    ],
    "unit_impact": 0,
    "minimal_quantity": "1",
    "date_formatted": "",
    "available_date": "",
    "id_image": -1,
    "list": "'27'"
  },
  "224129": {
    "attributes_values": {
      "4": "8.5"
    },
    "attributes": [
      28
    ],
    "unit_impact": 0,
    "minimal_quantity": "1",
    "date_formatted": "",
    "available_date": "",
    "id_image": -1,
    "list": "'28'"
  },
  "224161": {
    "attributes_values": {
      "4": "9"
    },
    "attributes": [
      29
    ],
    "unit_impact": 0,
    "minimal_quantity": "1",
    "date_formatted": "",
    "available_date": "",
    "id_image": -1,
    "list": "'29'"
  }
};
var contentOnly = false;
var Blank = 1;
var Format = 2;

这意味着当我打印出 s.text 时。我将得到上面代码的输出。小编辑:如果我尝试执行 if s.text.strip().startswith('var CombinationsFromController'): ，它将找不到该值，而且如果我以相反的方式更改它if 'var CombinationsFromController' in s.text.strip(): 它将打印出与上面相同的输出。

但是我的问题是，我只想打印出 var CombinationsFromController 并跳过其余部分，稍后我可以使用 json.loads 将值转换为 json，但在此之前我的问题是，我如何打印以便我可以设法只获得值 var CombinationsFromController？

编辑:可能解决了!

for s in product_li_tags:
            if 'var combinationsFromController' in s.text.strip():
                for line in s.text.splitlines():
                    if line.startswith('var combinationsFromController'):
                        get_full_text = line.strip()
                        get_config = get_full_text.split(" = ")
                        cut_text = get_config[1][:-1]
                        get_json_values = json.loads(cut_text)

Answer 1

如果我正确理解你的问题，你有一个代表 5 个 JavaScript 变量的 121 行字符串，并且你想要获取一个仅包含第二个变量的子字符串。

您可以按如下方式使用 Python 字符串操作:

start = special_code.split('\n').index('var combinationsFromController ={')
end   = special_code.split('\n')[start + 1:].index('var contentOnly = false;')
print('\n'.join(lines[start:end + 3]))

使用方法 str.index 查找您需要的 javascript 变量的出现次数。如果变量的顺序是任意的，即您不知道目标变量之后的下一个变量的名称是什么，您仍然可以使用类似的字符串操作来获取所需的子字符串。

lines = special_code.split('\n')
start = lines.index('var combinationsFromController ={')
end   = lines[-1]
for i, line in enumerate(lines[start + 1:]):
    if 'var' in line:
        end = start + i
        break
print('\n'.join(lines[start:end + 1]))