python - 嵌套棉花糖和 Sqlalchemy 包括子项

Question

我有一个与 2 个表相关的数据透视表 (postgres)。使用 Flask-marshmallow 和 sqlalchemy 我想从两个表的任何棉花糖模式中获取数据。例如:Table1Schema().dump(table1_object).first:并获取Table1记录与Table2的数据内部连接(Many=True):以下是我当前的代码:

仅供引用:我是 Flask 和 ORM 世界的新手:

我的模型:

class Permission(db.Model):
    __tablename__ = 'permission'
    permission_id = db.Column(db.Integer, primary_key=True)
    object = db.Column(db.String(70), nullable=False)

    def __init__(self, object):
        self.object = object


class Role(db.Model):
    __tablename__ = 'role'
    role_id = db.Column(db.Integer, primary_key = True)
    role_name = db.Column(db.String(70), nullable=False)
    role_permissions = db.relationship("RolePermission",backref='Role', lazy='dynamic')

    def __init__(self,role_name):
        self.role_name = role_name



class RolePermission(db.Model):
    __tablename__ = 'role_permission'
    role_permission_id = db.Column(db.Integer, primary_key=True)
    role_id = db.Column(db.Integer, db.ForeignKey('role.role_id', ondelete='CASCADE'), nullable =False)
    permission_id = db.Column(db.Integer, db.ForeignKey('permission.permission_id', ondelete='CASCADE'), nullable =False)

    def __init__(self,role_id,permission_id):
        self.role_id = role_id
        self.permission_id = permission_id

还有我的架构:

class RoleSchema(ma.Schema):
    role_id = fields.Integer(dump_only=True)
    role_name =  fields.String(required=True, validate=validate.Length(1))
    permissions = fields.Nested('RolePermissionSchema', many=True, only=('permission',))

    class Meta:
        model = Role
        fields = ('role_id', 'role_name', 'permissions')


class RolePermissionSchema(ma.Schema):
    role_permission_id = fields.Integer(dump_only=True)
    role_id = fields.Integer(required=True)
    permission_id = fields.Integer(required=True)
    role = fields.Nested('ROleSchema', many=False, only=('role_id', 'role_name',))
    permission = fields.Nested('PermissionSchema', many=False, only=('object', 'action',))




class PermissionSchema(ma.Schema):
    permission_id = fields.Integer(dump_only=True)
    object = fields.String(required=True, validate=validate.Length(1))
    role_permissions = fields.Nested('RolePermissionSchema', many=True, only=('role_permission_id', 'role_id',))
    class Meta:
        fields = ('object','action','role_permissions',)

序列化器:

 role = Role.query.filter_by(role_name=data['role_name']).filter_by(status=data['status']).first()
role_schema.dump(role).data

我想打印带有权限[]对象的Role o对象。然而从上面我能得到的只是角色内容。以下是输出:

{
        "role_name": "user",
        "status": true,
        "role_id": 4
    }

我如何得到这样的东西:

{
    "role_name": "user",
    "status": true,
    "role_id": 4,
    "permissions":[{
         "object":"user",
         "action":"create"},
          ]
}

Answer 1

存在一些命名问题，此处用注释行 # 表示。

class Role(db.Model):
   __tablename__ = 'role'
   role_id = db.Column(db.Integer, primary_key = True)
   role_name = db.Column(db.String(70), nullable=False)
   # This backref should probably be named role
   role_permissions = db.relationship("RolePermission",backref='Role', lazy='dynamic')

class RoleSchema(ma.Schema):
    role_id = fields.Integer(dump_only=True)
    role_name =  fields.String(required=True, validate=validate.Length(1))
    # This does not correspond to role_permissions in class Role
    permissions = fields.Nested('RolePermissionSchema', many=True, only=('permission',))

    class Meta:
        model = Role
        fields = ('role_id', 'role_name', 'permissions')

class RolePermissionSchema(ma.Schema):
   role_permission_id = fields.Integer(dump_only=True)
   role_id = fields.Integer(required=True)
   permission_id = fields.Integer(required=True)
   # Should be RoleSchema
   role = fields.Nested('ROleSchema', many=False, only=('role_id', 'role_name',))
   permission = fields.Nested('PermissionSchema', many=False, only=('object', 'action',))