python - 从字典和列表中删除重复元素并排序元素

Question

我想删除并排序我的元素列表

['elt9', 'elt19', 'elt1', 'elt2', 'elt3','elt9','elt2']

并得到

['elt1', 'elt2', 'elt3', 'elt9', 'elt19']

这是我的全部代码:

import itertools as it
import re
from collections import OrderedDict
from itertools import chain

L1 = ['elt1', 'elt2', 'elt3', 'elt4', 'elt5', 'elt6', 'elt9']
L2 = [['elt1','elt11'],['elt2','elt12'],['elt3','elt13'], ['elt4','elt14']]

def generate_combinations(L):    
    L_com = []
    for r in range(1, len(L)+1):
        L_com += list(it.combinations(L, r))           

    all_combination= []
    for i in L_com:
        for j in L2:
            all_combination.append(j+list(i))

    l = sorted(set(all_combination), key = lambda x : int(re.findall(r'\d+', x)[0]))
    with open('combinations.txt', 'w') as file_handler:
         for item in l:
             file_handler.write("{}\n".format(item))

if __name__ == "__main__":
    generate_combinations(L1)

我遇到了这个错误:

TypeError                                 Traceback (most recent call last)
<ipython-input-49-e0b599cc4158> in <module>()
      1 if __name__ == "__main__":
----> 2     generate_combinations(L1)

<ipython-input-45-81ef5db3553e> in  generate_combinations(L1)
     21 
     22     #sorted(set(all_combination), key=lambda x: int(x[3:]))
---> 23     l = sorted(set(all_combination), key = lambda x : int(re.findall(r'\d+', x)[0]))
     24 
     25     with open('combinations.txt', 'w') as file_handler:

TypeError: unhashable type: 'list'

Answer 1

将set与sorted结合使用:

l = ['elt9', 'elt19', 'elt1', 'elt2', 'elt3','elt9','elt2']
sorted(set(l), key=lambda x: int(x[3:]))

['elt1', 'elt2', 'elt3', 'elt9', 'elt19']