jquery - jquery页面上的多个依赖选择框

Question

您好，我正在尝试创建表单，其中有两个或多个相同的依赖选择框。问题是我可以从第一个选择框中进行选择，但无法弄清楚如何从其他选择框中进行选择。谁能帮我解决这个问题。

我无法从第三个选择框中进行选择。

这里是:JSFiddle

JS代码:

        $(document).ready(function() {
      $('select[name*="[]"]').each(function(){

        var attribute = {
        'shoes': ['standard'],
        'trous': ['male', 'female'],
        'shirt': ['blue', 'red', 'green', 'brown', 'yellow'],
        'hoodie': ['blue', 'red'],
        }

        var size = {
            'shoes': ['35', '36', '37', '38', '39', '40', '41', '42', '43', '44', '45', '46'],
            'trous': ['44', '46', '48', '50', '52', '54', '56', '58', '60', '62', '64'],
            'shirt': ['S', 'M', 'L', 'XL', 'XXL'],
            'hoodie': ['S', 'M', 'L', 'XL', 'XXL'],
        }

        $('select[name*="[]"]').change(function () {
        var $attribute = $(this).next('.attribute');
        var product = $(this).val(), attProd = attribute[product] || [];

        var html = $.map(attProd, function (attOpt) {
            return '<option value="' + attOpt + '">' + attOpt + '</option>'
        }).join('');
        $attribute.html(html)
       });

        ('select[name*="[]"]').change(function () {
        var $size = $('select').next('.size');
        var product = $(this).val(), sizeProd = size[product] || [];

        var htmlS = $.map(sizeProd, function(sProd){
            return '<option value="' + sProd + '">' + sProd + '</option>'
        }).join('');
        $size.html(htmlS)
        });
       });
    });

和 html 代码:

<div class="options">
    <select name="product[]" class="custom-select form-control-sm product">
        <option></option>
        <option value="shoes">Boots</option>
        <option value="trous">Trousers</option>
        <option value="shirt">Shirt</option>
        <option value="hoodie">Hoodie</option>
    </select>
    <select name="att[]" class="custom-select form-control-sm attribute">
    </select>
    <select name="size[]" class="custom-select form-control-sm size">
    </select>
   <input name="number[]" type="text" style="width: 50px"/>
</div>
<div class="options">
    <select name="product[]" class="custom-select form-control-sm product">
        <option></option>
        <option value="shoes">Boots</option>
        <option value="trous">Trousers</option>
        <option value="shirt">Shirt</option>
        <option value="hoodie">Hoodie</option>
    </select>
    <select name="att[]" class="custom-select form-control-sm attribute">
    </select>
    <select name="size[]" class="custom-select form-control-sm size">
    </select>
   <input name="number[]" type="text" style="width: 50px"/>
</div>

Answer 1

首先，您的 html 代码出错，因为您使用了两个具有相同 id 的 select:

<select name="att[]" id="attribute" class="custom-select form-control-sm attribute">

<select name="product[]" id="product" class="custom-select form-control-sm product">

然后我纠正你我纠正你JSFiddle在这里并且工作正常

$(document).ready(function(){
         $('select[name*="[]"]').each(function(){
             
            var attribute = {
            'shoes': ['standard'],
            'trous': ['male', 'female'],
            'shirt': ['blue', 'red', 'green', 'brown', 'yellow'],
            'hoodie': ['blue', 'red'],
            }
					
            
                        
 var size = {
            'shoes': ['35', '36', '37', '38', '39', '40', '41', '42', '43', '44', '45', '46'],
            'trous': ['44', '46', '48', '50', '52', '54', '56', '58', '60', '62', '64'],
            'shirt': ['S', 'M', 'L', 'XL', 'XXL'],
            'hoodie': ['S', 'M', 'L', 'XL', 'XXL'],
        }


            $('select[name*="[]"]').change(function () {
            var $attribute = $(this).next('.attribute');
             var $size = $(this).next('.attribute').next('.size');
             
            var product = $(this).val(), lcns = attribute[product] || [];
	          var product22 = $(this).val(), lcns22 = size[product] || [];
            
            var html = $.map(lcns, function(lcn){
                return '<option value="' + lcn + '">' + lcn + '</option>'
            }).join('');
           
              
            var html2 = $.map(lcns22, function(lcn){
                return '<option value="' + lcn + '">' + lcn + '</option>'
            }).join('');
           
            $attribute.html(html);
            $size.html(html2);
            });
        });
        });

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="options">
    <select name="product[]" class="custom-select form-control-sm product">
        <option></option>
        <option value="shoes">Boots</option>
        <option value="trous">Trousers</option>
        <option value="shirt">Shirt</option>
        <option value="hoodie">Hoodie</option>
    </select>
    <select name="att[]" class="custom-select form-control-sm attribute">
    </select>
    <select name="size[]" class="custom-select form-control-sm size">
    </select>
   <input name="number[]" type="text" style="width: 50px"/>
</div>
<div class="options">
    <select name="product[]" class="custom-select form-control-sm product">
        <option></option>
        <option value="shoes">Boots</option>
        <option value="trous">Trousers</option>
        <option value="shirt">Shirt</option>
        <option value="hoodie">Hoodie</option>
    </select>
    <select name="att[]" class="custom-select form-control-sm attribute">
    </select>
    <select name="size[]" class="custom-select form-control-sm size">
    </select>
   <input name="number[]" type="text" style="width: 50px"/>
</div>