javascript - 获取 typescript 中单独数组、AddedList和RemovedList中两个数组之间的差异

Question

这个问题已经有答案了:

Typescript difference between two arrays (6 个回答)

已关闭 4 年前。

我是 typescript 新手，我想找到一种正确的方法来解决我的问题。所以我有两个数组 A 和 B，我需要找到两个数组相对于数组 A 之间的差异，并在单独的数组中返回结果，其中 addArray 是什么，removedArray 是什么例如:

A = [1, 2, 3, 4];
B = [1, 5, 6, 7];
addArray =[5,6,7]
removedArray =[2,3,4]

寻找快速而优雅的方式

Answer 1

const A = [1, 2, 3, 4];
const B = [1, 5, 6, 7];
const difference = (left, right) => {
  let a = new Set(left);
  let b = new Set(right);
  return [...a].filter(x => !b.has(x))
}
const addArray = difference(B, A);
const removedArray = difference(A, B);

console.log({ addArray, removedArray });

引用文献:

• 2ality:ECMAScript 6 sets: union, intersection, difference

• MDN:Set : Implementing basic set operations