python - Python v3.7.x中，被调用函数如何获取调用函数的名称？

Question

Python 爱好者，

在 Python v3.7.x 或更高版本中，被调用函数如何获取调用函数的名称...而不将调用函数的名称作为参数进行编程？

在下面的代码示例中，如何用……嗯……调用函数的名称填充NAME_OF_CALLING_FUNCTION？ (比如说……与标准库有关？Dunders/Magic Names？)

• 需要明确的是:此协助请求并非涉及使用Python 的日志记录模块(此处仅用作示例)；这是关于被调用函数能够自动神奇地获取名称调用函数的值。

示例代码:

logging.basicConfig(filename='my_log_file.log',
    level = logging.DEBUG,
    format = A_VALID_FORMAT_STRING)

def logging_function(log_message):
    #Simplified for StackOverflow
    msg = str(NAME_OF_CALLING_FUNCTION) + ' DEBUG: Something...'
    logging.debug(msg)

def caller_one():
    #Simplified for StackOverflow
    logging_function(DIAGNOSTIC_MESSAGE_ONE)
    return(0)

def caller_two():
    #Simplified for StackOverflow
    logging_function(DIAGNOSTIC_MESSAGE_TWO)
    return(0)

def main():
    #Simplified for StackOverflow
    caller_one()
    caller_two()

理想情况下，当 caller_one() 和 caller_two() 执行时，my_log_file.log 将包含如下内容:

DATE/TIME Calling function: caller_one DEBUG: Something...
DATE/TIME Calling function: caller_two DEBUG: Something...

非常感谢您提供的任何帮助!

怀着感恩的心，飞机书写器

Answer 1

使用inspect模块。来自 this source :

import inspect
# functions
def whoami():
    return inspect.stack()[1][3]
def whosdaddy():
    return inspect.stack()[2][3]
def foo():
    print "hello, I'm %s, daddy is %s" % (whoami(), whosdaddy())
    bar()
def bar():
    print "hello, I'm %s, daddy is %s" % (whoami(), whosdaddy())
johny = bar
# call them!
foo()
bar()
johny()

hello, I'm foo, daddy is ?
hello, I'm bar, daddy is foo
hello, I'm bar, daddy is ?
hello, I'm bar, daddy is ?

根据您的情况:

msg = str(inspect.stack()[1].function) + ' DEBUG: Something...'

示例:

import inspect

def logging_function(log_message):
    #Simplified for StackOverflow
    msg = str(inspect.stack()[1].function) + ' DEBUG: Something...'
    print(msg)

def f1():
    logging_function("")

def f2():
    logging_function("")

f1()
f2()

f1 DEBUG: Something...
f2 DEBUG: Something...