javascript - 为什么我不能使用 jQuery 循环遍历我的 json 对象？

Question

我正在使用 jquery 循环 json 对象...但有些它似乎不起作用...

这是我的代码，

$.ajax({
      type: "POST",
      url: "Default.aspx/GetRecords",
      //      data: "{}",
      data: "{'currentPage':1,'pagesize':5}",
      contentType: "application/json; charset=utf-8",
      dataType: "json",
      success: function(jsonObj) {
          alert(jsonObj);
          for (var i = jsonObj.length - 1; i >= 0; i--) {
            var employee = jsonObj[i];
            alert(employee.Emp_Name);

当提醒我的 jsonObj 时，我得到了 [object Object] 但当我提醒 jsonObj.length 时，它显示 undefined 任何建议....

编辑:

使用下面的答案我无法迭代div，

$.each(jsonObj, function(i, employee) {
   $('<div class="resultsdiv"><br /><span class="resultName">' + employee[i].Emp_Name + '</span><span class="resultfields" style="padding-left:100px;">Category&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee[i].Desig_Name + '</span><br /><br /><span id="SalaryBasis" class="resultfields">Salary Basis&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee[i].SalaryBasis + '</span><span class="resultfields" style="padding-left:25px;">Salary&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee[i].FixedSalary + '</span><span style="font-size:110%;font-weight:bolder;padding-left:25px;">Address&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee[i].Address + '</span></div>').insertAfter('#ResultsDiv');
 });

我的 json 对象将是这个，

{
  "Table": [{
    "Row": "1",
    "Emp_Id": "3",
    "Emp_Name": "Jerome",
    "Address": "Madurai",
    "Desig_Name": "Supervisior",
    "SalaryBasis": "Monthly",
    "FixedSalary": "25000.00"
  }, {
    "Row": "2",
    "Emp_Id": "4",
    "Emp_Name": "Mohan",
    "Address": "Madurai",
    "Desig_Name": "Acc ",
    "SalaryBasis": "Monthly",
    "FixedSalary": "200.00"
  }, {
    "Row": "3",
    "Emp_Id": "5",
    "Emp_Name": "Murugan",
    "Address": "Madurai",
    "Desig_Name": "Mason",
    "SalaryBasis": "Weekly",
    "FixedSalary": "150.00"
  }, {
    "Row": "4",
    "Emp_Id": "6",
    "Emp_Name": "Ram",
    "Address": "Madurai",
    "Desig_Name": "Mason",
    "SalaryBasis": "Weekly",
    "FixedSalary": "120.00"
  }, {
    "Row": "5",
    "Emp_Id": "7",
    "Emp_Name": "Raja",
    "Address": "Madurai",
    "Desig_Name": "Mason",
    "SalaryBasis": "Weekly",
    "FixedSalary": "135.00"
  }]
}

我在 json 选项卡中通过 firebug 检查了这个

{“表”:[{“行”:“1...edSalary”:“135.00”}]}...

我得到的响应是

{"d":"{\"Table\" : [{\"Row\" : \"1\",\"Emp_Id\" : \"3\",\"Emp_Name\" : \"Jerome\",\"Address\" : \"Madurai\",\"Desig_Name\" : \"Supervisior\",\"SalaryBasis\" : \"Monthly\",\"FixedSalary\" : \"25000.00\"},{\"Row\" : \"2\",\"Emp_Id\" : \"4\",\"Emp_Name\" : \"Mohan\",\"Address\" : \"Madurai\",\"Desig_Name\" : \"Acc \",\"SalaryBasis\" : \"Monthly\",\"FixedSalary\" : \"200.00\"},{\"Row\" : \"3\",\"Emp_Id\" : \"5\",\"Emp_Name\" : \"Murugan\",\"Address\" : \"Madurai\",\"Desig_Name\" : \"Mason\",\"SalaryBasis\" : \"Weekly\",\"FixedSalary\" : \"150.00\"},{\"Row\" : \"4\",\"Emp_Id\" : \"6\",\"Emp_Name\" : \"Ram\",\"Address\" : \"Madurai\",\"Desig_Name\" : \"Mason\",\"SalaryBasis\" : \"Weekly\",\"FixedSalary\" : \"120.00\"},{\"Row\" : \"5\",\"Emp_Id\" : \"7\",\"Emp_Name\" : \"Raja\",\"Address\" : \"Madurai\",\"Desig_Name\" : \"Mason\",\"SalaryBasis\" : \"Weekly\",\"FixedSalary\" : \"135.00\"}]}"}

任何建议...

Answer 1

使用 jQuery 的 each 方法。 Docs .

success: function(jsonObj) {

         $.each(jsonObj, function(i, employee) {

            alert(employee.Emp_Name);

         }
}

此外，据我所知，alert() 本身不会显示 JSON 结构。

因为它是一个对象(而不是数组)，所以我认为它不会有长度属性。

此外，您是否有任何理由更喜欢在 for 循环中倒数而不是向上数？这是一个优化技巧吗？

更新

看到一些 JSON 示例后，即

{
   Table: [
      {
         Row: '1',
         Emp_Id: '3',
         Emp_Name: 'Jerome',
         Address: 'Madurai',
         Desig_Name: 'Supervisior',
         SalaryBasis: 'Monthly',
         FixedSalary: '25000.00'
      },
      {
         Row: '2',
         Emp_Id: '4',
         Emp_Name: 'Mohan',
         Address: 'Madurai',
         Desig_Name: 'Acc ',
         SalaryBasis: 'Monthly',
         FixedSalary: '200.00'
      },
      {
         Row: '3',
         Emp_Id: '5',
         Emp_Name: 'Murugan',
         Address: 'Madurai',
         Desig_Name: 'Mason',
         SalaryBasis: 'Weekly',
         FixedSalary: '150.00'
      },
      {
         Row: '4',
         Emp_Id: '6',
         Emp_Name: 'Ram',
         Address: 'Madurai',
         Desig_Name: 'Mason',
         SalaryBasis: 'Weekly',
         FixedSalary: '120.00'
      },
      {
         Row: '5',
         Emp_Id: '7',
         Emp_Name: 'Raja',
         Address: 'Madurai',
         Desig_Name: 'Mason',
         SalaryBasis: 'Weekly',
         FixedSalary: '135.00'
      }
   ]
}

您似乎希望像这样访问员工姓名

 $.each(jsonObj.table, function(i, employee) {

                alert(employee.Emp_Name);

             }