python - 如何修复 'else' 输出超过 1 个结果

Question

非常基本的问题，尝试输出一个数字是否可以被 3/5/both/none 整除，但 else 会在不成立时返回 2 个语句。我该如何解决这个问题？

我尝试移动 else 缩进的位置，第一次它不会输出不是 3 或 5 的倍数的数字，第二次它会输出两个答案。

while True:
    z = input("Please enter a number- to end the program enter z as -1 ")
    if z % 3 == 0 and z % 5 ==0:
        print("Your number is a multiple of 3 and 5")
    elif z % 3 == 0 and z % 5 != 0:
        print("Your number is a multiple of 3")
    elif  z % 3 != 0 and z % 5 ==0:
        print("Your number  is a multiple of 5")
    if z == -1:
        break
   else:
       print("Your number is not a multiple of 3 or 5")

即如果输入 67 您的号码不是预期的 3 或 5 的倍数。但是，如果输入 15，Your number is the multiple of 3 and 5 且 Your number is not a multiple of 3 or 5 就是意外输出。

Answer 1

如果您合并到目前为止的所有评论建议，您会得到如下内容:

while True:
    z = input("Please enter a number- to end the program enter z as -1 ")
    # cast to int
    z = int(z)
    # break early
    if z == -1:
        break
    elif z % 3 == 0 and z % 5 == 0:
        print("Your number is a multiple of 3 and 5")
    elif z % 3 == 0:
        print("Your number is a multiple of 3")
    elif z % 5 == 0:
        print("Your number is a multiple of 5")
    else:
        print("Your number is not a multiple of 3 or 5")