python - 如何从特定字典键的值列表中删除单词？

Question

我需要从字典列表中特定键的值中删除单词列表。

以下是我的数据的示例:

words = ['cloves', 'packed']

data = [{'title': 'Simple Enchiladas Verdes',
         'prep_time': '15 min',
         'cook_time': '30 min',
         'ingredients': ['chicken breast', 'tomato sauce', 'garlic cloves', 'fresh packed cilantro']
         'instructions': ['some text...'],
         'category': 'dessert',
         'cuisine': 'thai', 
         'article': ['some text...']
        },
        {...}, {...}]

期望的输出:

data = [{'title': 'Simple Enchiladas Verdes',
         'prep_time': '15 min',
         'cook_time': '30 min',
         'ingredients': ['chicken breast', 'tomato sauce', 'garlic', 'fresh cilantro']
        },
        {...}, {...}]

我尝试过不同的代码:

remove = '|'.join(words)
regex = re.compile(r'\b('+remove+r')\b', flags=re.IGNORECASE)

for dct in data:
    dct['ingredients']= list(filter(lambda x: regex.sub('', x), dct['ingredients']))

但这会返回以下错误:TypeError: sub() 缺少 1 个必需的位置参数:'string'

我尝试过的其他代码:

for dct in data:
    dct['ingredients']= list(filter(lambda x: x != words, dct['ingredients']))

for dct in data:
    dct['ingredients']=[[el for el in string if el in words ] for string in dct['ingredients']]

for dct in data:
    for string in dct['ingredients']:
        dct['ingredients'] = list(filter(lambda x: x not in words, dct['ingredients']))

但他们都没有解决我的问题。

Answer 1

为什么不使用 list 理解与 dictionary 理解:

data = [{k:([' '.join([s for s in x.split() if s not in words]) for x in v] if k == 'ingredients' else v) for k, v in i.items()} for i in data]