Javascript仅获取某个数组中包含的对象

Question

这个问题已经有答案了:

Filter array of objects based on another array in javascript (10 个回答)

已关闭 4 年前。

我有一个数组

const dataitems =  [
    {name:'test1', id:1},
    {name:'test2', id:2},
    {name:'test3', id:3}
  ]

const compares = [1,3]

所以我只想获取比较数组值中包含 id 的数据项的值

所以最后我希望得到一个最终数组

const ffinaldataitems =  [
    {name:'test1', id:1},
    {name:'test3', id:3}
  ]

排除 id 2

所以我尝试了以下方法，但卡住了

  let finaldataitems = []
  dataitems.forEach(item=>{
         if(item.id ) //stuck on how to check and push to the array
  })

我该如何继续

Answer 1

您可以尝试使用 Array.prototype.filter()

The filter() method creates a new array with all elements that pass the test implemented by the provided function.

和Array.prototype.includes()

The includes() method determines whether an array includes a certain value among its entries, returning true or false as appropriate.

const dataitems =  [
  {name:'test1', id:1},
  {name:'test2', id:2},
  {name:'test3', id:3}
];

const compares = [1,3];

let finaldataitems = dataitems.filter(item => compares.includes(item.id));

console.log(finaldataitems);