javascript - 将两个列表转换为 json

Question

我正在尝试将两个列表转换为 json。

例如:

l1 = ['a','b','a']
l2 = ['q','r','s']

应转换为:

[{
    "name": "g",
    "children": [{
            "name": "a",
            "children": [{
                "name": "q"
            }, {
                "name": "s"
            }]
        },
        {
            "name": "b",
            "children": [{
                "name": "r"
            }]
        }
    ]
}]

我最接近的是:

l1 = ['a','b','a']
l2 = ['q','r','s']

nameDict = {}
childrenDict = {}

l1 = l1.map(x => {
  return({name: x});
});
console.log(l1);

l2 = l2.map(x => {
  return({children: x});
});
console.log(l2);

var c = l1.map(function(e, i) {
  return [e, l2[i]];
});

console.log(JSON.stringify(c))

产生:

[[{"name":"a"},{"children":"q"}],
[{"name":"b"},{"children":"r"}],
[{"name":"a"},{"children":"s"}]]

如何组合产生的元素？ :

[{
    "name": "g",
    "children": [{
            "name": "a",
            "children": [{
                "name": "q"
            }, {
                "name": "s"
            }]
        },
        {
            "name": "b",
            "children": [{
                "name": "r"
            }]
        }
    ]
}]

Answer 1

免责声明:由于我们不知道 g 来自哪里，因此我只会构建根 children 数组。

由于您的数组具有相同的长度，因此您可以使用普通的 for 并与索引一起使用来处理两个数组。只需构建一个数组并检查每次迭代是否“子”已经存在。如果没有，请创建它。

l1 = ['a','b','a']
l2 = ['q','r','s']

let gChildren = []
for(let i = 0; i < l1.length; i++){
  let group = gChildren.find(c => c.name === l1[i])
  if(!group){
    group = { name: l1[i], children: [] }
    gChildren.push(group)
  }
  
  group.children.push({ name: l2[i] })
}

console.log(gChildren)