python-2.7 - 从字符串中排除标点符号/非字母字符的更好方法？

Question

我编写了这个程序来对文本文档中的单词进行分类和枚举。如果我不必用 string.translate() 挑出每一个可能的标点符号，代码会非常整洁......是否有可能，而不是排除特定情况，只允许字母顺序(也许还有数字)字符？

from sys import argv

script_, filename = argv

bang = open(filename, 'r+')
words = bang.read()
words = words.translate(None, ',')
words = words.translate(None, '"')
words = words.translate(None, '.')
words = words.translate(None, '...')
words = words.translate(None, '?')
words = words.translate(None, '!')
words = words.translate(None, ';')
words = words.translate(None, '-')
words = words.translate(None, '\'')
words = words.translate(None, '.\'')
words = words.translate(None, '(')
words = words.translate(None, ')')
words = words.translate(None, ':')
words = str(words)
words = words.lower()
liste = words.split()
sorte = sorted(liste)

i = 0
f = 'nullooosdfgkjlkjasdihaiwuehlfkj898'
z = 1
w = 0

for wordss in sorte:
    if f == wordss:
        z += 1
        w += 1
    elif f != wordss: 
        w += 1
        print "-", z
        z = 1
        i += 1
        print "%d. %s" % (i, wordss),
        f = wordss

print "\n\n word count - %d\n" % w

Answer 1

I want to list words in a text document

这个算法怎么样。在空白处拆分文本，然后去除标点符号。

>>> text = "'I wonder how many miles I've fallen by this time?' she said aloud."
>>> import string
>>> words = [x.strip(string.punctuation) for x in text.split()]
>>> words
['I', 'wonder', 'how', 'many', 'miles', "I've", 'fallen', 'by', 'this', 'time', 'she', 'said', 'aloud']

请参阅这与 don't 等缩略词对应。所以你可以区分 we're 和 were。