python - 仅打印嵌套列表中的偶数

Question

这就是我所拥有的:

mylist1 = [[1,2,3], [4,5,6], [7,8,9]]   

for i in mylist1:
    if i[0] % 2 == 0:
        print(i[0])
    if i[1] % 2 == 0:
        print(i[1])
    if i[2] % 2 == 0:
        print(i[2])

有没有更短的方法？

Answer 1

列表理解？

print('\n'.join(str(i) for sublist in mylist1 for i in sublist if i % 2 == 0))

更少的核心列表理解？

for sublist in mylist1:
    print('\n'.join(i for i in sublist if i % 2 == 0))

for循环？

for sublist in mylist1:
    for i in sublist:
        if i % 2 == 0:
            print(i)