spring - Jersey 自定义 ExceptionMapper 未在 400 Bad Request 上调用(验证失败时)

Question

我正在将 Jersey 与 Spring 一起用于 Web 服务。为了捕获异常并格式化发送给调用者的响应，我添加了一个 ExceptionMapper 的实现。

虽然当我从 Controller 内显式抛出异常时它被调用，但是当 json 字段验证失败时，异常映射器不会被调用并且发送的响应是 ** 可能不是 null (path = checkNotification.arg0.tyres, invalidValue = 空)
**

@Provider
public class GenericExceptionMapper implements ExceptionMapper<Throwable> {

    @Override
    public Response toResponse(Throwable ex) {
        System.out.println("Exception Mapper !!!");
        return Response.status(404).entity(ex.getMessage()).type("application/json").build();
    }
}


<servlet>
        <servlet-name>jersey-servlet</servlet-name>
        <servlet-class>
            org.glassfish.jersey.servlet.ServletContainer
        </servlet-class>
            <init-param>
                <param-name>jersey.config.server.provider.packages</param-name>
                <param-value>
                        com.help.rest.controller,
                        com.fasterxml.jackson.jaxrs.json
                </param-value>
            </init-param>
            <init-param>
                    <param-name>javax.ws.rs.Application</param-name>
                    <param-value>com.help.filter.FeatureRegistration</param-value>
            </init-param>
            <init-param>
                <param-name>jersey.config.beanValidation.enableOutputValidationErrorEntity.server</param-name>
                <param-value>true</param-value>
            </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

Jersey 版本是 2.22.1
Spring 版本是 4.2.4

我通过改变让它工作

 @Provider
    public class GenericExceptionMapper implements ExceptionMapper<Throwable> {

        @Override
        public Response toResponse(Throwable ex) {
            System.out.println("Exception Mapper !!!");
            return Response.status(404).entity(ex.getMessage()).type("application/json").build();
        }
    }

到

 @Provider
    public class GenericExceptionMapper implements ExceptionMapper<ConstraintViolationException> {

        @Override
        public Response toResponse(ConstraintViolationException ex) {
            System.out.println("Exception Mapper !!!");
            return Response.status(404).entity(ex.getMessage()).type("application/json").build();
        }
    }

虽然我能够捕捉到异常，但我没有得到约束失败的确切类和字段。

已解决
在 ContraintViolationException 中找到包含所有必填字段的 Set，可以使用 ex.getConstraintViolations() 访问

Answer 1

通过改变使它工作

 @Provider
    public class GenericExceptionMapper implements ExceptionMapper<Throwable> {

        @Override
        public Response toResponse(Throwable ex) {
            System.out.println("Exception Mapper !!!");
            return Response.status(404).entity(ex.getMessage()).type("application/json").build();
        }
    }

到

 @Provider
    public class GenericExceptionMapper implements ExceptionMapper<ConstraintViolationException> {

        @Override
        public Response toResponse(ConstraintViolationException ex) {
            System.out.println("Exception Mapper !!!");
            return Response.status(404).entity(ex.getMessage()).type("application/json").build();
        }
    }

要获取确切的异常详细信息，例如哪个字段未通过约束，请使用 ConstraintViolationException 的 getConstraintViolations()。该方法为所有约束违规提供了一个集合。