javascript - 检查值是否位于嵌套数组内部的更好方法 - Javascript

Question

我正在使用 Google Places API。我注意到，当我输入机构时，并不总是有邮政编码、国家/地区、城市，即使有，它们也不总是位于 address_components 数组内的同一索引中。

现在，我试图查找它是否具有上面列出的任何内容，以及它是否返回值。有没有更好的方法来实现这一目标:

getPlaceTypeValue(addressComponents: Places[], type: string): string {
    let value = null;
    for (const [i] of addressComponents.entries()) {
      if (addressComponents[i].types.includes(type)) {
        value = addressComponents[i].long_name;
        break;
      }
    }
    return value;
  } 
console.log(this.placesService.getPlaceTypeValue(
address.address_components, 'postal_code'));
//Returns 77500

数据

[
      {
        "long_name": "Hotel Zone",
        "short_name": "Hotel Zone",
        "types": [
          "sublocality_level_1",
          "sublocality",
          "political"
        ]
      },
      {
        "long_name": "Kukulcan Boulevard",
        "short_name": "Kukulcan Boulevard",
        "types": [
          "neighborhood",
          "political"
        ]
      },
      {
        "long_name": "Cancún",
        "short_name": "Cancún",
        "types": [
          "locality",
          "political"
        ]
      },
      {
        "long_name": "Quintana Roo",
        "short_name": "Q.R.",
        "types": [
          "administrative_area_level_1",
          "political"
        ]
      },
      {
        "long_name": "Mexico",
        "short_name": "MX",
        "types": [
          "country",
          "political"
        ]
      },
      {
        "long_name": "77500",
        "short_name": "77500",
        "types": [
          "postal_code"
        ]
      }
    ]

Answer 1

首先，我会改变这一点:

for (const [i] of addressComponents.entries()) {
  if (addressComponents[i].types.includes(type)) {

对此:

for (const {types} of addressComponents) {
  if (types.includes(type)) {

或者，如果您喜欢更实用的方法，请在单行 return 语句中使用 Array#find:

return (addressComponents.find(({types}) => types.includes(type)) || {}).long_name || null;

||仅当返回值 undefined 不适合您时才需要 null 部分。

速度

如果在您的问题中“更好”意味着“更快”，那么请使用老式的 for 循环:

for (let i = 0, len = addressComponents.length; i < len; i++) {
  if (addressComponents[i].types.includes(type)) {